从另一个 viewController 访问信息

Accessing information from another viewController

我是 swift 的新手,我正在尝试使用来自另一个 class 的名称数组重新填充一个 pickerview。我有这个 class 创建笔记的笔记,每个笔记都有一个 name/title,我正在尝试访问那些 names/title 并将它们放在 pickerview 中,任何人都可以帮助我。

import UIKit
var allNotes: [Note] = []
var currentNoteindex: Int = -1
var noteTable: UITableView?
let kAllNotes:String = "notes"

class Note: NSObject
{
    var date:String
    var note:String
    var name:String

    override init()
    {
        date = NSDate().description
        name = ""
        note = ""
    }

    func dictionary() -> NSDictionary
    {
        return ["note": note, "date": date, "name": name]
    }

我有两个不同的 pickerview,一个可以用,只是名字不对。

override func viewDidLoad()
{
    super.viewDidLoad()

    fileNamePicker.dataSource = self
    fileNamePicker.delegate = self

    gradePicker.dataSource = self
    gradePicker.delegate = self

}


func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int
{
    if pickerView == gradePicker
    {
        return grades.count
    }
    else
    {
        return allNotes.count
    }

}

func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String?
{
    if pickerView == gradePicker
    {
       return grades[row]
    }

    else
    {
         //This is where the Problem is, but I don't know how to fix it.
        let nameFiles = allNotes[currentNoteindex].name 
        return nameFiles[row]
    }

}

func numberOfComponents(in pickerView: UIPickerView) -> Int
{
    return 1
}

nameFiles 正在访问笔记中的姓名。

nameFiles[row] 不起作用,因为 nameFiles 不是数组。

如果你想 return 一个字符串,只需执行 return nameFiles。不过,请首先检查以确保 nameFiles 确实具有值!

您的 allNotes 数组似乎是空的。你有 initilaize 但似乎没有追加对象。在 Note class

中创建 initiliaze 方法
init(_ date: String, note: String, name: String) {
        self.date = date
        self.note = note
        self.name = name
    }

在您的 viewcontroller class 中尝试像这样附加。现在您可以在下方访问选择器视图方法:-

//You can append by doinf iteration based on your data
allNotes.append(Note(date: "value1", note: "Value", name: "name"))