如何使用 PHP 根据 Key 对数组的值求和

How to sum values of array based on Key using PHP

for ($row = 0; $row < 25; $row++) {
    $bQuery = 'Select date, billed from {$tableArray[$row][1]}';
    $bProvider = new CSqlDataProvider($bQuery, array('pagination'=>false));
    $Arr2 = $bProvider->getData();
    // merging array to get all loop records in single array
    $array_2 = array_merge($array_2, $Arr2);
}

然后print_r$array_2输出为:

Array
(
    [0] => Array
        (
            [date] => 2016-11-00
            [billed] => 100
        )
    [1] => Array
        (
            [date] => 2016-12-00
            [billed] => 400
        )
    [2] => Array
        (
            [date] => 2016-11-00
            [billed] => 200
        )
     // so on
)

我想在 date is same 中求和 billed。所以这是适用于它的我的代码。

$result = array();
foreach ($array_2 as $data) {
    @$result[$data['date']] += $data['billed'];
}

print_r($result);

$newresultGraph = array();
foreach ($result as $date => $billed) {
    $newresultGraph[] = array('date' => $date, 'billed' => $billed);
}

print_r($newresultGraph);

上面代码中的print_r($result)returns我的数据如下,它已经对同一日期的值求和了。

Array
(
    [2016-11-00] => 300
    [2016-12-00] => 400
)

然后在我上面的代码中,在另一个 foreach 循环之后,我像以前一样在数组中制作我的数据。当我print_r($newresultGraph),我的数据是这样的

Array
(
    [0] => Array
        (
            [date] => 2016-11-00
            [billed] => 300
        )

    [1] => Array
        (
            [date] => 2016-12-00
            [billed] => 400
        )

)

这对我来说非常有用..因为我的查询是这样的。

Select date, billed from table'

我只从 table 得到 date, billed 但现在我有另一个字段所以我的查询是这样的..

Select 
date, 
billed, 
((billed * rate) * (myValue) / 100) as my_rev,
((billed * rate) * (opValue) / 100) as op_rev,
From table

所以我有两个新值,它们是 my_revop_rev

然后print_r$array_2输出为:

Array
(
    [0] => Array
        (
            [date] => 2016-11-00
            [billed] => 100
            [my_rev] => 30
            [op_rev] => 70
        )
    [1] => Array
        (
            [date] => 2016-12-00
            [billed] => 400
            [my_rev] => 150
            [op_rev] => 250
        )
    [2] => Array
        (
            [date] => 2016-11-00
            [billed] => 200
            [my_rev] => 50
            [op_rev] => 150
        )
     // so on
)

这是正确的,

我想对一个日期的所有账单的价值求和,my_rev,op_rev。我不想对账单+my_rev+op_rev求和..

我希望我的数组如下所示:它应该将 billed 的所有值加到 billed 中,类似于 my_rev 和 op_rev。

就像下面的例子。

Array
(
    [0] => Array
        (
            [date] => 2016-11-00
            [billed] => 300
            [my_rev] => 80
            [op_rev] => 220
        )
[1] => Array
    (
        [date] => 2016-12-00
        [billed] => 400
        [my_rev] => 150
        [op_rev] => 250
    )

)

我上面的代码将我的 print_r($result) 变成这样:

Array
(
    [2016-11-00] => 600
    [2016-12-00] => 800
)

我该怎么办?还有其他建议吗?

这段代码可以做到:

$tmp_array = array();
foreach ($array as $val) {
    if (array_key_exists($val['date'], $tmp_array)) {
        $tmp_array[$val['date']]['billed'] += $val['billed'];
        $tmp_array[$val['date']]['my_rev'] += $val['my_rev'];
        $tmp_array[$val['date']]['op_rev'] += $val['op_rev'];
    } else {
        $tmp_array[$val['date']]['date'] = $val['date'];
        $tmp_array[$val['date']]['billed'] = $val['billed'];
        $tmp_array[$val['date']]['my_rev'] = $val['my_rev'];
        $tmp_array[$val['date']]['op_rev'] = $val['op_rev'];
    }
}

$result = array_values($tmp_array);

输出:

Array
(
    [0] => Array
        (
            [date] => 2016-11-00
            [billed] => 300
            [my_rev] => 80
            [op_rev] => 220
        )
    [1] => Array
        (
            [date] => 2016-12-00
            [billed] => 400
            [my_rev] => 150
            [op_rev] => 250
        )
    )
)

$tmp_array 以日期为键对数据进行分组,最后用连续的索引替换这些键。如果您更喜欢将日期保留为键 - 它更优化 - 或者不在乎,只需调用 $tmp_array $result 并删除最后一行。

只需像这样更改您的倒数第二个 foreach,然后打印结果数组,您会看到它会将值与它们的键相加。

$result = array();
foreach ($array_2 as $data) {
    @$result[$data['date']]['billed'] += $data['billed'];
    @$result[$data['date']]['my_rev'] += $data['my_rev'];
    @$result[$data['date']]['op_rev'] += $data['op_rev'];
}

如果需要,您可以相应地更改最后一个 foreach。

使用您的值的结果:

输入:

Array
(
[0] => Array
    (
        [date] => 2016-11-00
        [billed] => 100
        [my_rev] => 30
        [op_rev] => 70
    )

[1] => Array
    (
        [date] => 2016-12-00
        [billed] => 400
        [my_rev] => 150
        [op_rev] => 250
    )

[2] => Array
    (
        [date] => 2016-11-00
        [billed] => 200
        [my_rev] => 50
        [op_rev] => 150
    )

)

结果:

Array
(
[2016-11-00] => Array
    (
        [billed] => 300
        [my_rev] => 80
        [op_rev] => 220
    )

[2016-12-00] => Array
    (
        [billed] => 400
        [my_rev] => 150
        [op_rev] => 250
    )
)

有两种选择:

  • 计算 PHP
  • 中的总和
  • 计算 SQL
  • 中的总和

计算 PHP

中的总和

$sql = <<<SQL
SELECT
    date, 
    billed, 
    billed * rate * myValue / 100 AS my_rev,
    billed * rate * opValue / 100 AS op_rev
FROM
    table
SQL;

$provider = new CSqlDataProvider($sql, array(
    'pagination' => false,
));

$rows = $provider->getData();

$data = array();

foreach ($rows as $row) {
    $date = $row['date'];

    // initialize
    if (!array_key_exists($date, $data)) {
        $data[$date] = array(
            'date' => $date,
            'billed' => $row['billed',
            'my_rev' => $row['my_rev'],
            'op_rev' => $row['op_rev',
        );

        continue;
    }

    $data[$date]['billed'] += $row['billed'];
    $data[$date]['my_rev'] += $row['my_rev'];
    $data[$date]['op_rev'] += $row['op_rev'];
}

// sort by key, that is, sort by date
ksort($data);

// remove keys
$data = array_values($data);

var_dump($data);

计算总和 SQL

$sql = <<<SQL
SELECT
    date, 
    SUM(billed), 
    SUM(billed * rate * myValue / 100) AS my_rev,
    SUM(billed * rate * opValue / 100) AS op_rev
FROM
    table
GROUP BY
    date
ORDER BY
    date ASC
SQL;

$provider = new CSqlDataProvider($sql, array(
    'pagination' => false,
));

$rows = $provider->getData();

var_dump($rows);

您自己决定您更喜欢这些解决方案中的哪一个。但是,后者需要的代码较少PHP,毕竟数据库服务器也可以做一些工作,对吧?