在Ruby中，可以使用lambda 或Proc 调用方法来调用迭代器吗？

Question

我想创建一个迭代器，我可以将其传递给要调用的方法。

#!/usr/bin/env ruby

puts "------------------------------------"
puts "1 This works."
puts "------------------------------------"       
1.times {|who| puts "Position #{who} works!"}

puts "------------------------------------"
puts "2 This works."
puts "------------------------------------"       
aBlock = Proc.new { |who| puts "Position #{who} also works!" }       
2.times &aBlock

puts "------------------------------------"
puts "3 This works."
puts "------------------------------------"       
def eachIndex
  3.times { |i| yield i }
end

eachIndex &aBlock

puts "------------------------------------"
puts "4 This does not work."
puts "------------------------------------"       
iterator = lambda { |name| yield name }       
iterator.call(4) {|who| puts "Does not work #{who}:-("}

puts "------------------------------------"
puts "5 This does not work."
puts "------------------------------------"       
iterator = lambda { |name,&block| yield name }       
iterator.call(5) {|who| puts "Does not work #{who}:-("}

puts "------------------------------------"
puts "6 This does not work."
puts "------------------------------------"       
iterator = Proc.new { |name,&block| yield name }       
iterator.call(6) {|who| puts "Does not work #{who}:-(" }

lambda 或 proc 可以是 Ruby 中的迭代器吗？我想将它们作为参数传递给 class。

Answer 1

方法如下

iterator = -> (name, &block) { block.call name }
iterator.call(4) { |who| puts "It works now #{who} :)" }

P.S。请注意，我在这里为 lambda、-> 使用了一个名为 stabby lambda

的快捷方式

在Ruby中，可以使用lambda 或Proc 调用方法来调用迭代器吗？

In Ruby, can you use the lambda or or Proc call method to invoke an iterator?

ruby

lambda

iterator

proc