RegExp 将逗号分隔符替换为分号

Question

我在 PHP

中有字符串

$str = '1,"4052","B00K6ED81S",,"Bottle, white - 6,5 l, WENKO","Good design!","Bottle, white 6,5 l, WENKO",,,"item","23",23,"23",23,31.22,31.22,,1,,,,0,8,"4",,0,,0,0,,0,,0,0,,

有逗号分隔符。某处是空字段，某处是带引号的字段（作为产品名称）。问题在于将分隔符替换为分号，但不要在产品名称中使用逗号。我需要这个：

$str_replace = '1;"4052";"B00K6ED81S";;"Bottle, white - 6,5 l, WENKO";"Good design!";"Bottle, white 6,5 l, WENKO";;;"item";"23";23;"23";23;31.22;31.22;;1;;;;0;8;"4";;0;;0;0;;0;;0;0;;';

我试过这段代码：

$str = '1,"4052","B00K6ED81S",,"Bottle, white - 6,5 l, WENKO","Good design!","Bottle, white 6,5 l, WENKO",,,"item","23",23,"23",23,31.22,31.22,,1,,,,0,8,"4",,0,,0,0,,0,,0,0,,';

$str = preg_replace('/,,/', ',~~~,', $str);
$str = preg_replace('/,,/', ',~~~,', $str);

$pattern = '/(?<=\d),|(?<="),|~~~,/';
$str = preg_replace($pattern, ';', $str);

结果：

1;"4052";"B00K6ED81S";;"Bottle, white - 6;5 l, WENKO";"Good design!";"Bottle, white 6;5 l, WENKO";;;"item";"23";23;"23";23;31.22;31.22;;1;;;;0;8;"4";;0;;0;0;;0;;0;0;;

产品名称中的逗号也被替换为分号：

"Bottle, white - 6;5 l, WENKO"

如何更正 $pattern 以获得我需要的结果？

Answer 1

我只是想尝试编写一个可以用老式方法完成的代码。
它找到 " 并根据它是在它们之间还是在它们之外来替换或不替换。

$str = '1,"4052","B00K6ED81S",,"Bottle, white - 6,5 l, WENKO","Good design!","Bottle, white 6,5 l, WENKO",,,"item","23",23,"23",23,31.22,31.22,,1,,,,0,8,"4",,0,,0,0,,0,,0,0,0';

$pos=1; // set $pos to make sure while loop does not end directly.
$newstr = "";
$prevPos = 0;
if($str[0]=='"') $str = " " .$str; // add space if the first char is a "
$skip = false; // flag to know if replace should be done or not

while($pos != false){
    $pos = strpos($str, '"', $prevPos); // find " in string after prevPos
    $part = substr($str, $prevPos, $pos+1-$prevPos); // substring the part (first time it runs it will be '1,"' then '4052"')
    if($skip){ // if it's between two " (a string) skip the replace
        //echo "skip " . $part . "\n";
        $skip =!$skip; // change the flag
        $newstr .= $part;
    }else{ // if it's not in a string do the replace on the $part
        //echo "!skip " . $part . "\n";
        $newstr .= str_replace(",", ";", $part);    
        $skip =!$skip; // change the flag.
    }
    $prevPos = $pos+1; // set new $prevPos
}

// if the loop ends and there is no more " in the string we need to replace , to ; on the rest of the string.
// we know the loop ended at strlen($newstr), so that is the $part.
if($pos<strlen($str)) $newstr .= str_replace(",", ";", substr($str, strlen($newstr)));
echo $str . "\n";
echo $newstr;

https://3v4l.org/CnSh8
它实际上表现得很好。比我预期的更好的循环和所有 if 和字符串操作。

编辑；请注意，如果第一项是字符串，则它不起作用。我添加 space 只是为了确保标志的顺序正确。
这可以很容易地 trim 与 trim() 相结合。
https://3v4l.org/hNLAF

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