如何计算乘法次数 python

Question

我是 python 的新手，有一些问题想问

问题是如何计算乘数

有6个骰子架

   import random
from collections import Counter

amt = 1
point = 0
diceStand = 6
dice1 = random.randint(1,6)
dice2 = random.randint(1,6)
dice3 = random.randint(1,6)
dice4 = random.randint(1,6)
dice5 = random.randint(1,6)
dice6 = random.randint(1,6)
roll = [dice1,dice2,dice3,dice4,dice5,dice6]

print("Do you want to play a dice game?")
print("turn " , amt , " of 3")
print("You have", point,'point')
print("You Roll")

for k in range(1):
    print(roll)
    counts = Counter(roll)
    print (Counter(counts))

结果：

[4, 1, 5, 6, 1, 4]
Counter({4: 2, 1: 2, 5: 1, 6*1})

如何打印消息和计数器乘数比如 4*3 = 12 和 1*2 = 2 只有超过2次才会相乘

那么已经使用了4个骰子

但你也可以掷剩余的骰子，即 2 个骰子 1 次然后 12 和 2 将保存到点尝试 3 次后游戏结束

很想了解如何使用随机值和计数器谢谢

Answer 1

如果我没理解错的话，您想打印任何重复掷骰子的结果，例如如果你掷四次“2”，打印“2 * 4 = 8”

如果是这样的话，那么这样的事情就可以了：

import random

amt = 1
point = 0
diceStand = 6
dice1 = random.randint(1,6)
dice2 = random.randint(1,6)
dice3 = random.randint(1,6)
dice4 = random.randint(1,6)
dice5 = random.randint(1,6)
dice6 = random.randint(1,6)
roll = [dice1,dice2,dice3,dice4,dice5,dice6]

print("Do you want to play a dice game?")
print("turn " , amt , " of 3")
print("You have", point,'point')
print("You Roll")

for i in range(1,7):
    total = 0
    for die in roll:
        if i == die:
            total += 1
    print i, " * ", total, " = ", i*total

编辑：这是一个示例输出

Do you want to play a dice game?
('turn ', 1, ' of 3')
('You have', 0, 'point')
You Roll
1  *  1  =  1
2  *  0  =  0
3  *  2  =  6
4  *  2  =  8
5  *  1  =  5
6  *  0  =  0

如何计算乘法次数 python

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