Codeigniter CRUD 应用程序：更新记录时出错（尝试获取非对象的属性）

Question

我用 Codeigniter 3 组合了一个 CRUD 应用程序。更新表单通过控制器设置了数据验证：

更新功能：

public function update($customer_id) {
        // data validation
        $this->form_validation->set_rules('first_name', 'First name', 'required');
        $this->form_validation->set_rules('last_name', 'Last name', 'required');
        $this->form_validation->set_rules('email', 'Email address', 'required|valid_email');
        $this->form_validation->set_error_delimiters('<p class="error">', '</p>');

        if ($this->form_validation->run()) {
            $data = [
            // insert into these database table fields
            'first_name' => $this->input->post('first_name'),
            'last_name' => $this->input->post('last_name'),
            'email' => $this->input->post('email')
            ];
            $this->load->model('Customer');
            if ($this->Customer->updateCustomer($customer_id, $data)) {
                $this->session->set_flashdata('update-response','Customer successfully updated');
            } else {
                $this->session->set_flashdata('update-response','Failed to update customer');
            }
            redirect('home');
        } else {
        $data = [       
            'first_name' => $this->input->post('first_name'),
            'last_name' => $this->input->post('last_name'),
            'email' => $this->input->post('email'),
            'id' => $customer_id
        ];
        $this->load->view('update', array("customer" => $data));
    }
}

它通过 if，但不通过 else。

更新表格:

<?php echo form_open("home/update/{$customer->id}"); ?>

    <div class="form-group <?php if(form_error('first_name')) echo 'has-error';?>">
        <?php echo form_input('first_name', set_value('first_name', $customer->first_name),[
            'id' => 'first_name',
            'class' => 'form-control'
            ]);
        if(form_error('first_name')) echo '<span class="glyphicon glyphicon-remove"></span>';
        echo form_error('first_name'); ?>                                     
    </div>

    <div class="form-group">
        <?php echo form_submit('submit', 'Save', 'class = "btn btn-success btn-block"'); ?>
    </div>

<?php echo form_close(); ?>

更新模型是：

public function getAllCustomers($customer_id) {
    $query = $this->db->get_where('customers', array('id' => $customer_id));
    if ($query->num_rows() > 0) {
        return $query->row();
    }
}

public function updateCustomer($customer_id, $data) {
    return $this->db->where('id', $customer_id)->update('customers', $data);
}

更新查看:

<?php echo form_open("home/update/{$customer->id}"); ?>

编辑记录时出现此问题，输入无效数据，然后点击 "Save button":

Severity: Notice
Message: Trying to get property of non-object
Filename: views/update.php

这样的问题只出现在更新表单上。这可能是什么原因？

Answer 1

您没有将数据传递到您的视图，因此您收到警告

$this->load->view('update');

到

$this->load->view('update', array('customer'=>$your_array));

会是这样的

$this->load->view('update',array(
                 'customer'=>$this->Customer->updateCustomer($customer_id, $data)
              )
 );

Answer 2

请在加载视图中发送数据，例如... 例如

$data['customer'] =  $this->Customer->updateCustomer($customer_id, $data);

$this->load->view('update',$data);

然后获取 $customer->id 等数据..

您无法传递数据，这就是显示错误的原因

Trying to get property of non-object

Answer 3

您必须从控制器中的更新功能传递 $customer 对象。所以你的其他部分应该看起来像-

$customer = $this->Customer->getCustomer($customer_id);
$this->load->view('update',$customer);

Answer 4

在你的 else 中替换为：

} else {
        $data = [       
            'first_name' => $this->input->post('first_name'),
            'last_name' => $this->input->post('last_name'),
            'email' => $this->input->post('email'),
            'id' => $customer_id
        ];
        $this->load->view('update', array("customer" => $data));
    }

Codeigniter CRUD 应用程序：更新记录时出错（尝试获取非对象的属性）

Codeigniter CRUD app: error updating a record (trying to get property of non-object)

php

codeigniter

crud

Codeigniter CRUD 应用程序：更新记录时出错（尝试获取非对象的 属性）

Codeigniter CRUD app: error updating a record (trying to get property of non-object)

php

codeigniter

crud

Codeigniter CRUD 应用程序：更新记录时出错（尝试获取非对象的属性）