从 Int 数组中获取 Min() 值
Get Min() Value From Int Array
我正在使用以下语法创建一个 int 数组
int start = Math.Min(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
int end = Math.Max(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
end = end + 1;
int[] ang = Enumerable.Range(start, end - start).ToArray();
foreach (int a in ang) {int first = a.Min(); }
但是我有一个编译错误
'int' does not contain a definition for 'Min' and the best extension method overload 'Enumerable.Min(IEnumerable)' requires a receiver of type 'IEnumerable'
从整数数组中获取 MIN() 值的正确方法是什么?
int start = Math.Min(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
int end = Math.Max(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
end = end + 1;
int[] ang = Enumerable.Range(start, end - start).ToArray();
var minimumValue = ang.Min();
我正在使用以下语法创建一个 int 数组
int start = Math.Min(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
int end = Math.Max(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
end = end + 1;
int[] ang = Enumerable.Range(start, end - start).ToArray();
foreach (int a in ang) {int first = a.Min(); }
但是我有一个编译错误
'int' does not contain a definition for 'Min' and the best extension method overload 'Enumerable.Min(IEnumerable)' requires a receiver of type 'IEnumerable'
从整数数组中获取 MIN() 值的正确方法是什么?
int start = Math.Min(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
int end = Math.Max(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
end = end + 1;
int[] ang = Enumerable.Range(start, end - start).ToArray();
var minimumValue = ang.Min();