添加一个 int 到 char* 的中间（在 C 中）

Question

想知道如何在 char* 中间有一个 int，例如：

char * winning_message =
"Congratulations, you have finished the game with a score of " + INT_HERE +
"                 Press any key to exit...                   ";

Answer 1

有了这个：

char winning_message[128]; // make sure you have enough space!
sprintf(winning_message, "Congratulations, you have finished the game with a score of %i. Press any key to exit...", INT_HERE);

Answer 2

也许您正在寻找这样的东西？

char buf[256];  // make sure this is big enough to hold your entire string!
sprintf(buf, "Congratulations, you have finished the game with a score of %i\nPress any key to exit...", INT_HERE);

请注意，如果您的字符串最终比 sizeof(buf) 长，则上述内容是不安全的，sprintf() 将写入超过它的末尾并破坏您的堆栈。为避免这种风险，您可以改为调用 snprintf()：

char buf[256];  // make sure this is big enough to hold your entire string!
snprintf(buf, sizeof(buf), "Congratulations, you have finished the game with a score of %i\nPress any key to exit...", INT_HERE);

...唯一的缺点是 snprintf() 可能无法在每个 OS.

上使用

Answer 3

您可以使用：

char * winning_message;
asprintf(&winning_message,"Congratulations, you have finished the game with a score of %d\nPress any key to exit...\n", INT_HERE);

添加一个 int 到 char* 的中间（在 C 中）

Adding an int into middle of char* (In C)

c

char-pointer