从 PHP 中的变量中删除具有特定结尾的单词

Question

目前我有这个代码：

// main title of product
$maintitle = 'CHICKENBUFFET HOT WINGS';

// take first word from $maintitle and put in new variable
list($title1) = explode(' ', $maintitle);

// words that start with CHICKEN are removed and put in new variable
$title2 = preg_replace('/(CHICKEN)\w+/', '', $maintitle);

// echo titles
echo $title1;
echo $title2;

这很好用，但是我不想删除以 CHICKEN 开头的单词，而是删除以 BUFFET 结尾的单词。我认为它与我在 preg_replace 行中的正则表达式有关，但我似乎找不到正确的表达式。

提前致谢！

Answer 1

由于您需要以 BUFFET 结尾的字符串，请进行如下更改

$title2 = preg_replace('/\w+(BUFFET)/', '', $maintitle);

完整代码

$maintitle = 'CHICKENBUFFET HOT WINGS';

// take first word from $maintitle and put in new variable
list($title1) = explode(' ', $maintitle);

// words that start with CHICKEN are removed and put in new variable
$title2 = preg_replace('/\w+(BUFFET)/', '', $maintitle); // changed this line

// echo titles
echo $title1;
echo "<br/>";
echo $title2;

Answer 2

试试这个正则表达式：

#\w+BUFFET#

任何以 BUFFET 结尾的单词都会匹配。

<?php

// main title of product
$maintitle = 'CHICKENBUFFET HOT WINGS';

// take first word from $maintitle and put in new variable
list($title1) = explode(' ', $maintitle);

// words that start with CHICKEN are removed and put in new variable
$title2 = preg_replace('/\w+BUFFET/', '', $maintitle);

// echo titles
echo $title1."\n";
echo trim($title2);

这将输出：

CHICKENBUFFET 
HOT WINGS

在这里试试：https://3v4l.org/FbMjk

从 PHP 中的变量中删除具有特定结尾的单词

Remove words with specific ending from variable in PHP

php

regex

preg-replace