PHP preg_replace 没有硬编码就无法工作

Question

当我收到一封电子邮件时，我只想将这封电子邮件的一部分保存在数据库中，因此，我使用正则表达式删除了我不想要的部分。但是，这不起作用。

function emailToMessage($inbox, $emails){
$messages = [];

foreach ($emails as $email_number){

    # $overview contient les infos du mail
    $overview = imap_fetch_overview($inbox,$email_number,0);
    $headerInfos = imap_headerinfo($inbox,$email_number);
    $mailHeader = imap_fetchheader($inbox,$email_number);
    $structure = imap_fetchstructure($inbox,$email_number);
    $subject = (isset($overview[0]->subject)) ?$overview[0]->subject : 'Pas de sujet';
    $sender = $headerInfos->from[0]->mailbox . "@" . $headerInfos->from[0]->host;
    $body = imap_fetchbody($inbox,$email_number,1);

    $body = checkSubtype($structure, $body); // decode if the transfert encoding is base64 and change encoding to utf8
    $text = cleanMail($body, $mailHeader);

    #conversion de udate en format pouvant etre inséré dans mySql
    $mailDateAndTime = date("Y-m-d H:i:s", $overview[0]->udate);

    $message = [
        'title'     => $subject,
        'text'      => $text,
        'id_sender' => $sender,
        'mailDateAndTime' => $mailDateAndTime,
    ];

    $messages[] = $message;
    }
return $messages;
}

function cleanMail($text, $mailHeader){
    $clientMail = checkMailClient($mailHeader);

switch($clientMail){
    case "gmail":
    echo($text . "<br>");
    $gmail = preg_replace("/\s+[0-9]{4}-[0-9]{2}-[0-9]{2}\s+[0-9]{2}:[0-9]{2}\s+GMT\+[0-9]{2}:[0-9]{2}\s+(.)*\s+:(?:\s(.)*)*/i", '', $text);
    echo($gmail . "<br>");
    return $gmail;
    break;

如果

$body = "test

2017-09-11 11:55 GMT+02:00 XXX :

> frgthyjuki";

echo($text);和回声（$gmail）；都给我 :

test

2017-09-11 11:55 GMT+02:00 XXX :

> frgthyjuki

但是，如果我在 emailToMessage() 中（在 $body = checkSubtype($structure, $body); 和 $text = cleanMail($body, $mailHeader); 之间）或在 cleanMail( )，有效。

switch($clientMail){
    $text = "test

2017-09-11 11:55 GMT+02:00 XXX :

> frgthyjuki";

    case "gmail":
    echo($text . "<br>");
    $gmail = preg_replace("/\s+[0-9]{4}-[0-9]{2}-[0-9]{2}\s+[0-9]{2}:[0-9]{2}\s+GMT\+[0-9]{2}:[0-9]{2}\s+(.)*\s+:(?:\s(.)*)*/i", '', $text);
    echo($gmail . "<br>");
    return $gmail;
    break;

echo($text);会给

test

2017-09-11 11:55 GMT+02:00 XXX :

> frgthyjuki

和回声（$gmail）；将给出：

test

为什么只有当变量是硬编码时它才有效？我该怎么做才能解决它？

更新

function checkSubtype($structure, $body){
    $subtype = strtolower($structure->subtype);

    if($subtype == "alternative") {
        $encoding = $structure->parts[0]->parameters[0]->value;
        $encoding = strtolower($encoding);
        $transferEncoding = $structure->parts[0]->encoding;

        $body = checkIfBase64($body, $transferEncoding);
        $body = quoted_printable_decode($body);
        $body = changeToUTF8($body, $encoding);
    } else {
        $transferEncoding = $structure->encoding;
        $body = checkIfBase64($body, $transferEncoding);
    }
    return $body;
}

-

function checkIfBase64($text, $transferEncoding){
    if($transferEncoding == "3"){
        $text = base64_decode($text);
    }
    return $text;
}

function changeToUTF8($text, $encoding){
    if($encoding != "utf-8" && $encoding != 'utf8'){
    $text = utf8_encode($text);
    }
    return $text;
}

更新 2

我用 Thunderbird 和 Orange 进行了测试。

我不使用 Thunderbird（我在线检查我的 RegEx，它是正确的）但它适用于 Orange。

case "orange":
return preg_replace("/s*>(?:\s(?:.)*)*/i", '', $text);
break;

我真的不懂...

更新 3

我在没有可怕的解决方案的情况下重试，它适用于以前的代码。很奇怪...

Answer 1

这是一个糟糕的解决方案，但它确实有效...

case "gmail":
    $step1 = preg_replace("/\s+/i", '#', $text);
    $step2 = preg_replace("/#*[0-9]{4}-[0-9]{2}-[0-9]{2}#+[0-9]{2}:[0-9]{2}#+GMT\+[0-9]{2}:[0-9]{2}#+(.)*#*:(?:#(.)*)*/i", '', $step1);
    return preg_replace("/#/i", ' ', $step2);
    break;

PHP preg_replace 没有硬编码就无法工作

PHP preg_replace doesn't work without hardcode

php

regex

function

preg-replace