仅选择出现在其他因素的每个水平中的那些水平的因素

Selecting only those levels of a factor which appear in each level of other factor

我只想select那些出现在Loc每个级别的Trt级别(通常出现在每个大型数据集的Loc级别) .

Loc <- rep(paste0("L", 1:2), c(6, 4))
Trt <- c(rep(paste0("T", 1:3), times = 2), rep(paste0("T", 1:2), times = 2))
set.seed(12345)
Y   <- c(rnorm(n=5, mean = 50, sd = 5), NA, rnorm(n=4, mean = 50, sd = 5)) 
df1 <- data.frame(Loc, Trt, Y)
df1

   Loc Trt        Y
1   L1  T1 52.92764
2   L1  T2 53.54733
3   L1  T3 49.45348
4   L1  T1 47.73251
5   L1  T2 53.02944
6   L1  T3       NA
7   L2  T1 40.91022
8   L2  T2 53.15049
9   L2  T1 48.61908
10  L2  T2 48.57920

需要输出

   Loc Trt        Y
   L1  T1 52.92764
   L1  T2 53.54733
   L1  T1 47.73251
   L1  T2 53.02944
   L2  T1 40.91022
   L2  T2 53.15049
   L2  T1 48.61908
   L2  T2 48.57920

这可以使用

来实现
    library(dplyr)
    df1 %>% filter(Trt != "T3")

这里我知道了外观的样式。我正在寻找更通用的解决方案。

您实质上是在尝试找出 df1$Loc 的每个级别中存在哪些 df1$Trt 值。 dplyr 中可能有一些我不知道的好方法。在基础 R 中你可以这样做:

dirty <- lapply( levels(df1$Loc), function(x) df1$Trt[df1$Loc == x])
clean <- do.call(intersect, dirty)

df1[df1$Trt %in% clean, ]
#    Loc Trt        Y
# 1   L1  T1 52.92764
# 2   L1  T2 53.54733
# 4   L1  T1 47.73251
# 5   L1  T2 53.02944
# 7   L2  T1 40.91022
# 8   L2  T2 53.15049
# 9   L2  T1 48.61908
# 10  L2  T2 48.57920

在最后一步中,您也可以坚持使用您的 dplyr 解决方案:

df1 %>% filter(Trt %in% clean)

这是另一种基于 R 的想法。我们根据 Loc 拆分 Trt,并使用 Reduceintersect 来查找所有公共元素。我们使用这些元素来索引原始数据框,即

i1 <- Reduce(intersect, split(df1$Trt, df1$Loc))
df1[df1$Trt %in% i1,]

这给出了,

  Loc Trt        Y
1   L1  T1 52.92764
2   L1  T2 53.54733
4   L1  T1 47.73251
5   L1  T2 53.02944
7   L2  T1 40.91022
8   L2  T2 53.15049
9   L2  T1 48.61908
10  L2  T2 48.57920

使用data.table,一个可能的解决方案是

library(data.table)
setDT(df1)[df1[, uniqueN(Loc), by = Trt][V1 == df1[, uniqueN(Loc)]], on = "Trt"][, -"V1"]
   Loc Trt        Y
1:  L1  T1 52.92764
2:  L1  T1 47.73251
3:  L2  T1 40.91022
4:  L2  T1 48.61908
5:  L1  T2 53.54733
6:  L1  T2 53.02944
7:  L2  T2 53.15049
8:  L2  T2 48.57920

解释

Loc的独特关卡总数为

df1[, uniqueN(Loc)]
[1] 2

每个TrtLoc的唯一级别数是

df1[, uniqueN(Loc), by = Trt]
   Trt V1
1:  T1  2
2:  T2  2
3:  T3  1

包含Loc所有关卡的Trt关卡是

df1[, uniqueN(Loc), by = Trt][V1 == df1[, uniqueN(Loc)]]
   Trt V1
1:  T1  2
2:  T2  2

现在,此权利与 df1 合并并从结果中删除了辅助列:

df1[df1[, uniqueN(Loc), by = Trt][V1 == df1[, uniqueN(Loc)]], on = "Trt"][, -"V1"]