SQL Server 2016 max in partition by select 语句不起作用

Question

我正在尝试通过分区语句return 分组集的最小和最大日期时间。最小行有效，但最大行是 returning 未分组结果的最大日期。 SQL Server 2016。我错过了什么？

SELECT 
    [temp_Emp], [temp_EmpID], [temp_Date], [Temp_Start], [Temp_End],
    MIN(Temp_Start) OVER (PARTITION BY temp_EmpID, temp_Date ORDER BY Temp_Start, Temp_End) AS 'Start',
    MAX(Temp_End) OVER (PARTITION BY temp_EmpID, temp_Date ORDER BY Temp_Start, Temp_End) AS 'End'
FROM 
    tmp_startend

结果：

 temp_EmpID temp_Date   Temp_Start  Temp_End    Start   End
 300    7/08/2017   7/08/2017 8:00  7/08/2017 8:15  7/08/2017 8:00  7/08/2017 8:15
 300    7/08/2017   7/08/2017 8:15  7/08/2017 8:30  7/08/2017 8:00  7/08/2017 8:30
 300    7/08/2017   7/08/2017 9:00  7/08/2017 10:00 7/08/2017 8:00  7/08/2017 10:00
 300    7/08/2017   7/08/2017 9:15  7/08/2017 14:30 7/08/2017 8:00  7/08/2017 14:30
 300    7/08/2017   7/08/2017 9:30  7/08/2017 14:00 7/08/2017 8:00  7/08/2017 14:30
 300    7/08/2017   7/08/2017 10:00 7/08/2017 13:00 7/08/2017 8:00  7/08/2017 14:30
 300    7/08/2017   7/08/2017 10:00 7/08/2017 14:30 7/08/2017 8:00  7/08/2017 14:30
 300    7/08/2017   7/08/2017 14:00 7/08/2017 15:00 7/08/2017 8:00  7/08/2017 15:00

Answer 1

省略 order by。这使得值累积：

SELECT [temp_Emp], [temp_EmpID],[temp_Date],[Temp_Start],[Temp_End],
       min(Temp_Start) over (partition by temp_EmpID, temp_Date) as [Start],
       max(Temp_End) over (partition by temp_EmpID, temp_Date) as [End]
FROM tmp_startend;

min() 恰好起作用了，因为 order by 将最小值放在首位——因此累积 min() 与整体 min() 相同。

SQL Server 2016 max in partition by select 语句不起作用

SQL Server 2016 max in partition by select statement not working

sql

sql-server

window-functions

sql-server-2016