PHP 两次的时差
Time Defference with Two Times in PHP
我有两次像下面这样:
$c _time = 11:32 AM
$t_time = 03:48 PM
现在我想找出 00:00:00
格式的差异
我该如何解决这个问题?
谢谢
试试这个:-
<?php
$datetime1 = new DateTime('11:32 AM');
$datetime2 = new DateTime('03:48 PM');
$interval = $datetime1->diff($datetime2);
echo "<pre/>";print_r($interval);
echo $interval->format('%H:%I:%S');
?>
输出:-
DateInterval Object
(
[y] => 0
[m] => 0
[d] => 0
[h] => 4
[i] => 16
[s] => 0
[invert] => 0
[days] => 0
)
04:16:00
如果您使用的是 Laravel,您可以使用 Carbon
进行一些简单的比较:
$c_time = "11:36 AM";
$t_time = "03:48 PM";
$c = Carbon::createFromFormat("H:i a", $c_time);
$t = Carbon::createFromFormat("H:i a", $t_time);
$minutes = $c->diffInMinutes($t); // returns 256 minutes, you can use either Carbon or pure DateTime objects to convert this
试试这个简单的解决方案:
$dt1 = new DateTime('11:32 AM');
$dt2 = new DateTime('03:48 PM');
echo $dt1->diff($dt2)->format('%H:%I:%S');
我有两次像下面这样:
$c _time = 11:32 AM
$t_time = 03:48 PM
现在我想找出 00:00:00
格式的差异我该如何解决这个问题?
谢谢
试试这个:-
<?php
$datetime1 = new DateTime('11:32 AM');
$datetime2 = new DateTime('03:48 PM');
$interval = $datetime1->diff($datetime2);
echo "<pre/>";print_r($interval);
echo $interval->format('%H:%I:%S');
?>
输出:-
DateInterval Object
(
[y] => 0
[m] => 0
[d] => 0
[h] => 4
[i] => 16
[s] => 0
[invert] => 0
[days] => 0
)
04:16:00
如果您使用的是 Laravel,您可以使用 Carbon
进行一些简单的比较:
$c_time = "11:36 AM";
$t_time = "03:48 PM";
$c = Carbon::createFromFormat("H:i a", $c_time);
$t = Carbon::createFromFormat("H:i a", $t_time);
$minutes = $c->diffInMinutes($t); // returns 256 minutes, you can use either Carbon or pure DateTime objects to convert this
试试这个简单的解决方案:
$dt1 = new DateTime('11:32 AM');
$dt2 = new DateTime('03:48 PM');
echo $dt1->diff($dt2)->format('%H:%I:%S');