对一行中的所有列求和

Question

如何获得所有行的总结果？（对于 ORACLE）

SELECT
 NAME,
 SUM(CASE WHEN ASSIST_1 = 'YES' THEN 1 END) WEEK1,
 SUM(CASE WHEN ASSIST_2 = 'YES' THEN 1 END) WEEK2,
 SUM(CASE WHEN ASSIST_3 = 'YES' THEN 1 END) WEEK3,
FROM TABLE_NAME
 WHERE GROUP BY NAME;

我有这样的结果：名称 week1 week2 week3

Anne    1 2 3
Bob     3 1 0
Charlie 4 5 1

我想要这个结果：

Anne    1 2 3
Bob     3 1 0
Charlie 4 5 1
Total   8 8 4

Answer 1

How can I get a total results of all my rows?

通过使用 group by 子句的 rollup() 扩展。像这样（只是一个例子）：

-- sample of date from your question
 with t1(uname, c1, c2, c3) as(
     select 'Anne'   , 1, 2, 3 from dual union all
     select 'Bob'    , 3, 1, 0 from dual union all
     select 'Charlie', 4, 5, 1 from dual
  )
  -- actual query
  select case grouping(uname) 
           when 0 then uname 
           else 'Total' end 
         as uname1
       , sum(c1) as c1
       , sum(c2) as c2
       , sum(c3) as c3  
    from t1
   group by rollup(uname) 
   order by grouping(uname)

结果：

UNAME1          C1         C2         C3
------- ---------- ---------- ----------
Anne             1          2          3
Bob              3          1          0
Charlie          4          5          1
Total            8          8          4


4 rows selected.

Answer 2

使用 UNION ALL 和 SUM 值

WITH t1(name, week1, week2, week3) AS
  ( SELECT 'Anne', 1, 2, 3 FROM dual
  UNION ALL
  SELECT 'Bob', 3, 1, 0 FROM dual
  UNION ALL
  SELECT 'Charlie', 4, 5, 1 FROM dual
  ),
  s AS
  (SELECT 'Total' name,
    SUM(week1) week1,
    SUM(week2) week2,
    SUM(week2) week3
  FROM t1
  )
SELECT * FROM t1
UNION ALL
SELECT * FROM s;

结果：

NAME    WEEK1   WEEK2   WEEK3
Anne    1        2       3
Bob     3        1       0
Charlie 4        5       1
Total   8        8       8

Answer 3

基于@Nicholas 的回答：

SELECT
   CASE GROUPING(NAME) WHEN 0 THEN NAME ELSE 'TOTAL' END AS NAME,
   SUM (WEEK1) AS WEEK1,
   SUM (WEEK2) AS WEEK2,
   SUM (WEEK3) AS WEEK3
      FROM (
         SELECT
            NAME,
            SUM(CASE WHEN ASSIST_1 = 'YES' THEN 1 END) WEEK1,
            SUM(CASE WHEN ASSIST_2 = 'YES' THEN 1 END) WEEK2,
            SUM(CASE WHEN ASSIST_3 = 'YES' THEN 1 END) WEEK3,
               FROM TABLE_NAME
               WHERE GROUP BY (NAME)
          GROUP BY ROLLUP(NAME)
          ORDER BY GROUPING(NAME);

给出这个结果：

Anne    1 2 3
Bob     3 1 0
Charlie 4 5 1
Total   8 8 4

对一行中的所有列求和

Sum all columns in a row

oracle

rdbms