Select 记录来自不同 table 基于连接的计数

Question

我想获取用户在不同 table 中输入的记录数。数据库的模式是：

+-----------------------+  
| Survey Master         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   |  
| Username       |      |
| FamilyMasterId | FK   |
+----------------+------+

+------------+------+  
| Family Master     |  
+------------+------+   
| Field      | Key  |  
+------------+------+  
| id         | PK   |   
+------------+------+

+-----------------------+  
| Family Detail         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   | 
| FamilyMasterId | FK   |   
+----------------+------+

+-----------------------+  
| Travel Master         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   | 
| FamilyDetailId | FK   |   
+----------------+------+

+-----------------------+  
| Travel Detail         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   | 
| TravelMasterId | FK   |   
+----------------+------+

我想查看每个用户在每个 table 中创建的记录数，如下所示：

  Username   SurveyMaster   FamilyMaster   FamilyDetail   TravelMaster   TravelDetail  
 ---------- -------------- -------------- -------------- -------------- -------------- 
  User001    59             47             36             26             12            
  User002    88             76             64             42             25            
  User003    49             44             35             25             15            
  User004    77             69             55             45             37

查看以下链接后：

Find Records from Different Tables
Select count(*) from multiple tables
http://www.sqlines.com/mysql/how-to/join-different-tables-based-on-condition
http://www.informit.com/articles/article.aspx?p=30875&seqNum=5
SQL: Combine Select count(*) from multiple tables

我能够编写此查询，但它在所有列中提供相同的记录：

SELECT USERNAME, COUNT(USERNAME) SURVEYMASTER, COUNT(USERNAME) FAMILYMASTER, COUNT(USERNAME) FAMILYDETAIL, COUNT(USERNAME) TRAVELMASTER, COUNT(USERNAME) TRAVELDETAIL FROM 
((SELECT CREATEUSER USERNAME FROM SURVEYMASTER
) 
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
) 
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID
)
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID
)
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID
INNER JOIN TRAVELDETAIL TD ON TM.ID = TD.TRAVELMASTERID
)
) T
GROUP BY USERNAME
ORDER BY USERNAME

编辑

关系描述如下：

FamilyMasterId 是 SurveyMaster 和 FamilyDetail 中的外键 tables.
FamilyDetailId 是 TravelMaster 中的外键 table。
TravelMasterId 是 TravelDetail 中的外键 table。

Answer 1

如果我们考虑性能，这可能不是完美的解决方案，但它可以提供所需的结果

SELECT  sm.Username ,
        COUNT(*) SurveyMaster ,
        COUNT(FamilyMasterId) FamilyMaster ,
        fd.FamilyDetail ,
        tm.TravelMaster ,
        td.TravelDetail
FROM    SurveyMaster sm
        JOIN ( SELECT   Username ,
                        COUNT(fd.id) FamilyDetail
               FROM     SurveyMaster sm
                        JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id
                        JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId
               GROUP BY Username
             ) fd ON sm.Username = fd.Username
        JOIN ( SELECT   Username ,
                        COUNT(tm.id) TravelMaster
               FROM     SurveyMaster sm
                        JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id
                        JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId
                        JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId
               GROUP BY Username
             ) tm ON sm.Username = tm.Username
        JOIN ( SELECT   Username ,
                        COUNT(td.id) TravelDetail
               FROM     SurveyMaster sm
                        JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id
                        JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId
                        JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId
                        JOIN TravelDetail td ON tm.Id = td.TravelMasterId
               GROUP BY Username
             ) td ON sm.Username = td.Username
GROUP BY sm.Username ,
        fd.FamilyDetail ,
        tm.TravelMaster ,
        td.TravelDetail;

Select 记录来自不同 table 基于连接的计数

Select records counts from different table on the basis of join

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