意外的标记: ) 在 findAll 和 findByKeyIn 与 Spring 和 Eclipselink JPA
Unexpected token: ) in findAll and findByKeyIn with Spring and Eclipselink JPA
为什么以下两个简单的集成测试失败,使用 Spring 1.5.4.RELEASE 和 Eclipselink 2.6.4?
@RunWith(SpringRunner.class)
@SpringBootTest(classes = {MyApp.class})
@WebAppConfiguration
@DirtiesContext(classMode = ClassMode.BEFORE_CLASS)
public class DbDummyIT {
@Autowired
private DbDummyRepository repo;
@Test
public void findAllFails() {
List<String> keys = Arrays.asList("1", "2");
List<DbDummy> result = repo.findAll(keys);
assertThat(result.isEmpty()).isTrue();
}
@Test
public void findByKeyInFails() {
List<String> keys = Arrays.asList("1", "2");
List<DbDummy> result = repo.findByKeyIn(keys);
assertThat(result.isEmpty()).isTrue();
}
}
基于:
@Entity
@UuidGenerator(name = DbDummy.KEY_GENERATOR)
public class DbDummy {
public static final String KEY_GENERATOR = "KeyGenerator";
@Id
@Column(name = ColumnName.KEY, nullable = false)
@GeneratedValue(generator = KEY_GENERATOR)
public String key;
}
@Repository
public interface DbDummyRepository extends JpaRepository<DbDummy, String> {
List<DbDummy> findByKeyIn(List<String> keys);
}
调用 find
查询时,两个测试都失败并出现 JpaSystemException。错误信息是:
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.6.4.v20160829-44060b6): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLSyntaxErrorException: unexpected token: ) in statement [SELECT Key FROM DBDUMMY WHERE (Key IN ((?,?)))]
Error Code: -5581
Call: SELECT Key FROM DBDUMMY WHERE (Key IN ((?,?)))
bind => [2 parameters bound]
Query: ReadAllQuery(referenceClass=DbDummy sql="SELECT Key FROM DBDUMMY WHERE (Key IN (?))")
这个说法在我看来确实是错误的。 Key IN ((?, ?))
不查询双值元组列表吗?不应该将字符串列表查询为 Key IN (?, ?)
?
尝试将类型更改为 Collection<String> keys
而不是 List<String> keys
。根据documentation,这应该是Collection,可能Spring认为是你的自定义方法,不是查询方法。
看起来像是 Eclipselink 中的一个长期存在的错误:https://bugs.eclipse.org/bugs/show_bug.cgi?id=349477
为什么以下两个简单的集成测试失败,使用 Spring 1.5.4.RELEASE 和 Eclipselink 2.6.4?
@RunWith(SpringRunner.class)
@SpringBootTest(classes = {MyApp.class})
@WebAppConfiguration
@DirtiesContext(classMode = ClassMode.BEFORE_CLASS)
public class DbDummyIT {
@Autowired
private DbDummyRepository repo;
@Test
public void findAllFails() {
List<String> keys = Arrays.asList("1", "2");
List<DbDummy> result = repo.findAll(keys);
assertThat(result.isEmpty()).isTrue();
}
@Test
public void findByKeyInFails() {
List<String> keys = Arrays.asList("1", "2");
List<DbDummy> result = repo.findByKeyIn(keys);
assertThat(result.isEmpty()).isTrue();
}
}
基于:
@Entity
@UuidGenerator(name = DbDummy.KEY_GENERATOR)
public class DbDummy {
public static final String KEY_GENERATOR = "KeyGenerator";
@Id
@Column(name = ColumnName.KEY, nullable = false)
@GeneratedValue(generator = KEY_GENERATOR)
public String key;
}
@Repository
public interface DbDummyRepository extends JpaRepository<DbDummy, String> {
List<DbDummy> findByKeyIn(List<String> keys);
}
调用 find
查询时,两个测试都失败并出现 JpaSystemException。错误信息是:
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.6.4.v20160829-44060b6): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLSyntaxErrorException: unexpected token: ) in statement [SELECT Key FROM DBDUMMY WHERE (Key IN ((?,?)))]
Error Code: -5581
Call: SELECT Key FROM DBDUMMY WHERE (Key IN ((?,?)))
bind => [2 parameters bound]
Query: ReadAllQuery(referenceClass=DbDummy sql="SELECT Key FROM DBDUMMY WHERE (Key IN (?))")
这个说法在我看来确实是错误的。 Key IN ((?, ?))
不查询双值元组列表吗?不应该将字符串列表查询为 Key IN (?, ?)
?
尝试将类型更改为 Collection<String> keys
而不是 List<String> keys
。根据documentation,这应该是Collection,可能Spring认为是你的自定义方法,不是查询方法。
看起来像是 Eclipselink 中的一个长期存在的错误:https://bugs.eclipse.org/bugs/show_bug.cgi?id=349477