在 Python 3.6 中检测用户输入的最低值

Question

我必须根据用户输入计算一组值的平均成绩，同时在计算平均值之前舍弃最低成绩。除了降低最低值的代码外，我什么都有。我尝试使用 min 函数，但是在循环内打印时我得到 "TypeError: 'int' object is not iterable." 知道如何解决这个问题吗？谢谢！

numuser=eval(input("How many users are there?: "))
numgrade=eval(input("How many grades will there be for each user?: "))
usercount=0
gradecount=0

while usercount <= numuser:
    name=input("Please enter the user's first and last name: ")
    gradetot=0
    while gradecount < numgrade:
        gradeval=eval(input("Please enter the grade: "))
        gradetot=gradetot+gradeval
        gradecount=gradecount+1

low = min(gradeval)
tot = gradetot-low

print("The average grade for", name, "is :", tot/gradecount)
numuser=numuser-1
usercount=usercount+1
gradecount=0

Answer 1

我已经修改了您的申请，请参阅下文并尝试了解需要进行哪些更改才能满足您的要求。

numuser=eval(input("How many users are there : " ))
numgrade=eval(input("How many grades will there be for each user : " ))
usercount=0
gradecount=0
gradeval = [] # you need a array to store a range of values

while usercount <= numuser:
    name=input("Please enter the user's first and last name : " )
    gradetot=0
    while gradecount < numgrade:
        val=eval(input("Please enter the grade :  " ))
        gradeval.append(val)
        gradetot=gradetot+val
        gradecount=gradecount+1

low = min(gradeval)# min function need a range of values
tot = gradetot-low

print("The average grade for : ", name, "is : ", tot/gradecount)
numuser=numuser-1
usercount=usercount+1
gradecount=0

在 Python 3.6 中检测用户输入的最低值

Detect lowest value from user input in Python 3.6

python

min