instagram preg_replace 获取预览

Question

我编写了这段代码来将 instagram 嵌入更改为预览图像

$strings     = array('https://instagram.com/p/BanWWFtBz6O', 'BanWWFtBz6O');
$searchs     = array('/instagram\.com\/p\/([a-zA-Z0-9]+)/', '/([a-zA-Z0-9]+)/');
$replaces    = array('instagram.com/p//media/?size=l', 'https://instagram.com/p//media/?size=l');    
$soc_instagram = preg_replace($searchs,$replaces,$strings);

但我对该代码有疑问，首先，当我尝试将第一个值放入 $strings https://instagram.com/p/BanWWFtBz6O it change to https://instagram.com/p/BanWWFtBz6O/media/?size=l 时应该没问题

当我尝试从 $strings BanWWFtBz6O 中输入第二个值时出现的问题（只有 instagram 的 ID post）它变为

https://instagram.com/p/https/media/?size=l://https://instagram.com/p/instagram/media/?size=l.https://instagram.com/p/com/media/?size=l/https://instagram.com/p/p/media/?size=l/https://instagram.com/p/BaQsAubg6H3/media/?size=l/https://instagram.com/p/media/media/?size=l/?https://instagram.com/p/size/media/?size=l=https://instagram.com/p/l/media/?size=l

我错过了什么吗？请帮忙

============================================= ======================= youtube 代码怎么样？

$string     = array('https://www.youtube.com/watch?v=QTrPMYYGam8', 'QTrPMYYGam8');
$search     = array('/www.youtube\.com\/watch\?v=([a-zA-Z0-9_\-+?:]+)/', '/([a-zA-Z0-9_\-+?:]+)/');
$replace    = array('i.ytimg.com/vi//hqdefault.jpg', 'https://i.ytimg.com/vi//hqdefault.jpg');    
$soc_youtube = preg_replace($search,$replace,$string);

Answer 1

单个替换即可：

$strings     = array('https://instagram.com/p/BanWWFtBz6O', 'BanWWFtBz6O');
$searchs     = array('~(?:https://instagram\.com/p/)?([a-zA-Z0-9]+)~');
$replaces    = array('https://instagram.com/p//media/?size=l');    
$soc_instagram = preg_replace($searchs,$replaces,$strings); 

print_r($soc_instagram);

输出：

Array
(
    [0] => https://instagram.com/p/BanWWFtBz6O/media/?size=l
    [1] => https://instagram.com/p/BanWWFtBz6O/media/?size=l
)

对于youtube使用相同的方法：

$string     = array('https://www.youtube.com/watch?v=QTrPMYYGam8', 'QTrPMYYGam8');
$search     = array('~(?:https://www.youtube\.com/watch\?v=)?([a-zA-Z0-9_\-+?:]+)~');
$replace    = array('https://i.ytimg.com/vi//hqdefault.jpg');    
$soc_youtube = preg_replace($search,$replace,$string);

instagram preg_replace 获取预览

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