使用 underscore.js in AngularJS 合并两个数组

Merge two Arrays using underscore.js in AngularJS

我有两个 api 请求,都得到了 JSON 的结果。第一个请求是 "account" 请求,第二个是 "Container" 请求。现在:

这是 JSON 帐户的结果:

account: [
{
    accountId: "123456789",
    fingerprint: null,
    name: "Account2",
    path: "accounts/123456789",
},

这是 JSON 容器的结果:

{
    accountId: "123456789",
    containerId: "123****",
    domainName: null,
    fingerprint: "123*****",
    name: "Container23",
    path: "accounts/123456789/containers/123******",
    publicId: "GTM-****"
},

如您所见,容器结果包含 accountid,因此我试图合并这两个结果,使其成为这样的组合(容器):

{
    accountId: "123456789",
    name: "Account2",           <------ THIS is what i want to merge
    containerId: "123****",
    domainName: null,
    fingerprint: "123*****",
    name: "Container23",
    path: "accounts/123456789/containers/123******",
    publicId: "GTM-****"
},

记住有很多容器和帐户,而不仅仅是一个块。

我尝试使用下划线:

var mergedList = _.map($scope.GTMcontainers, function(data){
                                return _.extend(data, _.findWhere($scope.account, { id: data.accountId }));
                            });
                            console.log(mergedList);

这是我的 AngularJS

function getContainer() {
   $http.get("http://******")
        .then(function (response) {
            $scope.GTMcontainers = response.data;
            console.log(response);
            $scope.loading = false;
        })
        .then(function () {
            $http.get("http://******")
                .then(function (response2) {
                    $scope.account = response2.data;
                    console.log(response2);

                    var mergedList = _.map($scope.GTMcontainers, function(data){
                        return _.extend(data, _.findWhere($scope.account, { id: data.accountId }));
                    });
                    console.log(mergedList);
                })
        })
}

使用这个下划线得到与我请求的完全相同的 JSON 结果(没有合并)。

希望有人对此有经验。

谢谢

更新:

使用简单 javascript

var accounts = [
{
accountId: "123456789",
fingerprint: null,
name: "Account2",
path: "accounts/123456789",
},{
accountId: "123456780",
fingerprint: null,
name: "Account3",
path: "accounts/123456789",
}]

var containers =[{
accountId: "123456789",
containerId: "123****",
domainName: null,
fingerprint: "123*****",
name: "Container23",
path: "accounts/123456789/containers/123******",
publicId: "GTM-****"
},{
accountId: "123456780",
containerId: "123****",
domainName: null,
fingerprint: "123*****",
name: "Container24",
path: "accounts/123456789/containers/123******",
publicId: "GTM-****"
}]

var result=[];
containers.forEach(function(item){
var temp=accounts.find(function(d){return d.accountId == item.accountId});
if(temp)
item.name = temp.name;
result.push(item);
})

console.log(result);

我遇到过那个问题,我知道我得到了回复,但数据没有合并。所以我使用了回调。

    function getContainer(callback) {
       $http.get("http://******")
            .then(function (response) {
                $scope.GTMcontainers = response.data;
                console.log(response);
                $scope.loading = false;
            })
            .then(function () {
                $http.get("http://******")
                    .then(function (response2) {
                        $scope.account = response2.data;
                        console.log(response2);
                        if(response && response2){
                        callback(response,response2);
}


                    })
            })
    }

函数调用时--

getContainer(function(array1,array2){
   if(array1 && array2 && array1.length>0 && array2.length>0){
var mergedList = _.map(array1, function(data){
                                return _.extend(data, _.findWhere(array2, { id: data.accountId }));
                            });
                            console.log(mergedList);
}
})