SQL Server 2008 R2:WHERE 中的多个值完全匹配
SQL Server 2008 R2: Exact match of multiple values in WHERE
我有以下 table:
create table person
(
id int,
name varchar(20),
games varchar(20)
);
insert into person values(1,'A','Cricket'),(1,'A','F1'),(2,'B','Cricket'),(3,'C','Cricket'),(3,'C','F1')
预期结果:
id name games
--------------
1 A Cricket
1 A F1
3 C Cricket
3 C F1
我的尝试 1:
SELECT * FROM person
WHERe games = 'Cricket'
AND games = 'F1'
输出:无
我的尝试 2:
SELECT * FROM person
WHERe games IN('Cricket','F1')
输出:
id name games
-------------------
1 A Cricket
1 A F1
2 B Cricket ---This should not come
3 C Cricket
3 C F1
SELECT
*
FROM person a
WHERE
games IN('Cricket','F1') AND
(
SELECT COUNT(Id)
FROM person
WHERE
Id = a.Id
) = 2
或更通用
;WITH model AS
(
SELECT * FROM (VALUES('Cricket'),('F1')) a(Games)
)
SELECT
a.*
FROM
person a
INNER JOIN
model b
ON
a.games = b.games
WHERE
(
SELECT COUNT(Id)
FROM person
WHERE
Id = a.Id
) =
(
SELECT COUNT(*)
FROM model
)
你们太亲密了:)
SELECT * FROM person
WHERE games IN ('Cricket','F1') AND Name IN ('A', 'C')
您还可以计算超过 1 个值的地方(然后有多个值,然后将它们与 table 内部连接以匹配行)
select x.id,b.games,b.name from (
select id,count(id) as Total from person
group by id
having count(id) > 1
) x
inner join person b on x.id = b.id
结果
首先,按游戏名称分组,然后select参加了超过1场比赛。
select a.* from
person as a,
(
select id,count(*) as total
from
person
where
games in ('Cricket','F1')
group by id,name
)as b
where
a.id = b.id
and b.total >=2
输出:
id name games
1 A Cricket
1 A F1
3 C Cricket
3 C F1
一种可能性是使用 OVER
子句来计算您定义的过滤器中每个 ID 的游戏数量:
;WITH t AS
(
SELECT *,
COUNT(id) OVER(PARTITION BY id) AS cnt
FROM person
WHERE games IN('Cricket','F1')
)
SELECT id, name, games FROM t
WHERE cnt > 1
我有以下 table:
create table person
(
id int,
name varchar(20),
games varchar(20)
);
insert into person values(1,'A','Cricket'),(1,'A','F1'),(2,'B','Cricket'),(3,'C','Cricket'),(3,'C','F1')
预期结果:
id name games
--------------
1 A Cricket
1 A F1
3 C Cricket
3 C F1
我的尝试 1:
SELECT * FROM person
WHERe games = 'Cricket'
AND games = 'F1'
输出:无
我的尝试 2:
SELECT * FROM person
WHERe games IN('Cricket','F1')
输出:
id name games
-------------------
1 A Cricket
1 A F1
2 B Cricket ---This should not come
3 C Cricket
3 C F1
SELECT
*
FROM person a
WHERE
games IN('Cricket','F1') AND
(
SELECT COUNT(Id)
FROM person
WHERE
Id = a.Id
) = 2
或更通用
;WITH model AS
(
SELECT * FROM (VALUES('Cricket'),('F1')) a(Games)
)
SELECT
a.*
FROM
person a
INNER JOIN
model b
ON
a.games = b.games
WHERE
(
SELECT COUNT(Id)
FROM person
WHERE
Id = a.Id
) =
(
SELECT COUNT(*)
FROM model
)
你们太亲密了:)
SELECT * FROM person
WHERE games IN ('Cricket','F1') AND Name IN ('A', 'C')
您还可以计算超过 1 个值的地方(然后有多个值,然后将它们与 table 内部连接以匹配行)
select x.id,b.games,b.name from (
select id,count(id) as Total from person
group by id
having count(id) > 1
) x
inner join person b on x.id = b.id
结果
首先,按游戏名称分组,然后select参加了超过1场比赛。
select a.* from
person as a,
(
select id,count(*) as total
from
person
where
games in ('Cricket','F1')
group by id,name
)as b
where
a.id = b.id
and b.total >=2
输出:
id name games
1 A Cricket
1 A F1
3 C Cricket
3 C F1
一种可能性是使用 OVER
子句来计算您定义的过滤器中每个 ID 的游戏数量:
;WITH t AS
(
SELECT *,
COUNT(id) OVER(PARTITION BY id) AS cnt
FROM person
WHERE games IN('Cricket','F1')
)
SELECT id, name, games FROM t
WHERE cnt > 1