SQL Server 2008 R2:WHERE 中的多个值完全匹配

SQL Server 2008 R2: Exact match of multiple values in WHERE

我有以下 table:

create table person
(
    id int,
    name varchar(20),
    games varchar(20)
);

insert into person values(1,'A','Cricket'),(1,'A','F1'),(2,'B','Cricket'),(3,'C','Cricket'),(3,'C','F1')

预期结果:

id name games
--------------
1   A   Cricket
1   A   F1
3   C   Cricket
3   C   F1

我的尝试 1:

SELECT * FROM person
WHERe games = 'Cricket' 
AND games = 'F1'

输出:无

我的尝试 2:

SELECT * FROM person
WHERe games IN('Cricket','F1')

输出:

id  name    games
-------------------
1   A   Cricket
1   A   F1
2   B   Cricket     ---This should not come
3   C   Cricket
3   C   F1
SELECT 
*
FROM person a
WHERE 
    games IN('Cricket','F1')    AND
    (
        SELECT COUNT(Id)
        FROM person
        WHERE 
            Id =  a.Id
    ) = 2

或更通用

;WITH model AS
(
    SELECT * FROM (VALUES('Cricket'),('F1')) a(Games)
)
SELECT 
    a.*
FROM 
    person a
INNER JOIN
    model   b
ON
    a.games = b.games
WHERE   
    (
        SELECT COUNT(Id)
        FROM person
        WHERE 
            Id =  a.Id
    ) =
    (
        SELECT COUNT(*) 
        FROM model
    )

你们太亲密了:)

SELECT * FROM person
WHERE games IN ('Cricket','F1') AND Name IN ('A', 'C')

您还可以计算超过 1 个值的地方(然后有多个值,然后将它们与 table 内部连接以匹配行)

select x.id,b.games,b.name from (
select id,count(id) as Total from person

group by id
having count(id) > 1
) x
inner join person b on x.id = b.id

结果

首先,按游戏名称分组,然后select参加了超过1场比赛。

select a.* from 
person as a,
(
    select id,count(*) as total 
    from
    person
    where
    games in ('Cricket','F1')
    group by id,name
)as b
where
a.id = b.id
and b.total >=2

输出:

id  name    games
1   A       Cricket
1   A       F1
3   C       Cricket
3   C       F1

一种可能性是使用 OVER 子句来计算您定义的过滤器中每个 ID 的游戏数量:

;WITH t AS
(
    SELECT *,
    COUNT(id) OVER(PARTITION BY id) AS cnt
    FROM person
    WHERE games IN('Cricket','F1')
)
SELECT id, name, games FROM t
WHERE cnt > 1