基于多个字段对集合中的记录进行排名

Question

╔════════════════════╦═══════════╦══════════╦═══════╦══════╗
║      ENDTIME       ║ TRAILERID ║ POSITION ║ STORE ║ STOP ║
╠════════════════════╬═══════════╬══════════╬═══════╬══════╣
║ 11/7/2017 15:15:44 ║       145 ║ L1       ║ BOS   ║    1 ║
║ 11/7/2017 15:16:57 ║       145 ║ L2       ║ NY    ║    3 ║
║ 11/7/2017 15:17:24 ║       145 ║ R1       ║ NY    ║    2 ║
║ 11/7/2017 15:17:57 ║       145 ║ R2       ║ NY    ║    1 ║
║ 11/7/2017 15:18:26 ║       145 ║ L3       ║ CT    ║    2 ║
║ 11/7/2017 15:34:24 ║       145 ║ R3       ║ CT    ║    1 ║
║ 11/7/2017 16:02:01 ║       999 ║ L1       ║ NJ    ║    2 ║
║ 11/7/2017 16:22:33 ║       999 ║ R1       ║ NJ    ║    1 ║
║ 11/7/2017 16:23:14 ║       999 ║ L2       ║ WA    ║    3 ║
║ 11/7/2017 16:27:16 ║       999 ║ R2       ║ WA    ║    2 ║
║ 11/7/2017 16:27:46 ║       999 ║ L3       ║ WA    ║    1 ║
╚════════════════════╩═══════════╩══════════╩═══════╩══════╝

我正在尝试将停止字段更改为如下所示

╔════════════════════╦═══════════╦══════════╦═══════╦══════╗
║      ENDTIME       ║ TRAILERID ║ POSITION ║ STORE ║ STOP ║
╠════════════════════╬═══════════╬══════════╬═══════╬══════╣
║ 11/7/2017 15:15:44 ║       145 ║ L1       ║ BOS   ║    3 ║
║ 11/7/2017 15:16:57 ║       145 ║ L2       ║ NY    ║    2 ║
║ 11/7/2017 15:17:24 ║       145 ║ R1       ║ NY    ║    2 ║
║ 11/7/2017 15:17:57 ║       145 ║ R2       ║ NY    ║    2 ║
║ 11/7/2017 15:18:26 ║       145 ║ L3       ║ CT    ║    1 ║
║ 11/7/2017 15:34:24 ║       145 ║ R3       ║ CT    ║    1 ║
║ 11/7/2017 16:02:01 ║       999 ║ L1       ║ NJ    ║    2 ║
║ 11/7/2017 16:22:33 ║       999 ║ R1       ║ NJ    ║    2 ║
║ 11/7/2017 16:23:14 ║       999 ║ L2       ║ WA    ║    1 ║
║ 11/7/2017 16:27:16 ║       999 ║ R2       ║ WA    ║    1 ║
║ 11/7/2017 16:27:46 ║       999 ║ L3       ║ WA    ║    1 ║
╚════════════════════╩═══════════╩══════════╩═══════╩══════╝

我的尝试是使用 row_number 和排名，但我无法获得正确的结果。给我第一个 table 结果。

SELECT ps.ENDTIME, ps.TRUCKID as TRAILERID, ps.CONTAINERPOSITION as POSITION,ps.STORE,RANK() OVER( PARTITION by ps.STORE  ORDER BY ps.ENDTIME DESC)AS STOP 
FROM TRAILERDATA ps
ORDER BY ps.ENDTIME ASC

最重要的是，即使 ENDTIME 的顺序不正确，也要按排名相同的商店组进行标记。

Answer 1

示例数据

DECLARE @T TABLE 
    (EndTime datetime2(0), TrailerID int, Position varchar(50), Store varchar(50));
INSERT INTO @T (EndTime, TrailerID, Position, Store) VALUES
('2017-11-07 15:15:44',145,'L1','BOS'),
('2017-11-07 15:16:57',145,'L2','NY'),
('2017-11-07 15:17:24',145,'R1','NY'),
('2017-11-07 15:17:57',145,'R2','NY'),
('2017-11-07 15:18:26',145,'L3','CT'),
('2017-11-07 15:34:24',145,'R3','CT'),
('2017-11-07 16:02:01',999,'L1','NJ'),
('2017-11-07 16:22:33',999,'R1','NJ'),
('2017-11-07 16:23:14',999,'L2','WA'),
('2017-11-07 16:27:16',999,'R2','WA'),
('2017-11-07 16:27:46',999,'L3','WA');

查询

WITH
CTE
AS
(
    SELECT
        EndTime, TrailerID, Position, Store
        ,MAX(EndTime) OVER (PARTITION BY TrailerID, Store) AS SortingTime
    FROM @T
)
SELECT
    EndTime, TrailerID, Position, Store
    ,SortingTime
    ,DENSE_RANK() OVER (PARTITION BY TrailerID ORDER BY SortingTime DESC) AS Stop
FROM CTE
ORDER BY TrailerID, Stop DESC, EndTime;

结果

+---------------------+-----------+----------+-------+---------------------+------+
|       EndTime       | TrailerID | Position | Store |     SortingTime     | Stop |
+---------------------+-----------+----------+-------+---------------------+------+
| 2017-11-07 15:15:44 |       145 | L1       | BOS   | 2017-11-07 15:15:44 |    3 |
| 2017-11-07 15:16:57 |       145 | L2       | NY    | 2017-11-07 15:17:57 |    2 |
| 2017-11-07 15:17:24 |       145 | R1       | NY    | 2017-11-07 15:17:57 |    2 |
| 2017-11-07 15:17:57 |       145 | R2       | NY    | 2017-11-07 15:17:57 |    2 |
| 2017-11-07 15:18:26 |       145 | L3       | CT    | 2017-11-07 15:34:24 |    1 |
| 2017-11-07 15:34:24 |       145 | R3       | CT    | 2017-11-07 15:34:24 |    1 |
| 2017-11-07 16:02:01 |       999 | L1       | NJ    | 2017-11-07 16:22:33 |    2 |
| 2017-11-07 16:22:33 |       999 | R1       | NJ    | 2017-11-07 16:22:33 |    2 |
| 2017-11-07 16:23:14 |       999 | L2       | WA    | 2017-11-07 16:27:46 |    1 |
| 2017-11-07 16:27:16 |       999 | R2       | WA    | 2017-11-07 16:27:46 |    1 |
| 2017-11-07 16:27:46 |       999 | L3       | WA    | 2017-11-07 16:27:46 |    1 |
+---------------------+-----------+----------+-------+---------------------+------+

在结果中您可以看到 SortingTime 如何计算您需要的 DENSE_RANK。本质上，SortingTime 定义了按 TrailerID 和 Store 分组，还方便地提供了一种排序方式。

上面的查询依赖于 EndTime 对于不同的 Stores 是不同的。更具体地说，MAX 时间不同。如果您有两个具有相同最大值 EndTime 的 Stores，则查询将为它们分配相同的 Stop。

如果有可能，则将 Store 添加到 ORDER BY:

WITH
CTE
AS
(
    SELECT
        EndTime, TrailerID, Position, Store
        ,MAX(EndTime) OVER (PARTITION BY TrailerID, Store) AS SortingTime
    FROM @T
)
SELECT
    EndTime, TrailerID, Position, Store
    ,SortingTime
    ,DENSE_RANK() OVER (PARTITION BY TrailerID ORDER BY SortingTime DESC, Store) AS Stop
FROM CTE
ORDER BY TrailerID, Stop DESC, EndTime;

基于多个字段对集合中的记录进行排名

Rank records in sets based on multiple fields

sql

sql-server

sql-server-2008

sql-server-2008-r2