使用 CoAPthon 库将 json 有效负载作为 return 值从 CoAP 服务器发送到 GET 方法

Question

我正在使用 CoAPthon 创建服务器，每当调用 get 方法时，它应该 return 一个 json 有效负载，下面是我的代码片段：

from coapthon.resources.resource import Resource
from coapthon.server.coap import CoAP 
import json

class res(Resource):
   def __init__(self,name="Res",coap_server=None):
      super(res,self).__init__(name,coap_server,visible=True,observable=True,allow_children=True)
      with open("/home/pratik/Iot_datamodels/IoT-openiot-DataModels/oic.r.temperature.json","r") as f:
        value = json.load(f)
      self.payload=value['definitions']
      self.resource_type = "oic.r.temperature"
      self.content_type = "application/json"
      self.interface_type = "oic.if.a"

   def render_GET(self,request):
    print json.dumps({"e":[{ "n": "temperature", "v":23.5,"u":"degC" }]})
    return json.dumps({"e":[{ "n": "temperature", "v":23.5,"u":"degC" }]}))

class CoAPServer(CoAP):
  def __init__(self, host, port, multicast=False):
    CoAP.__init__(self,(host,port),multicast)
    self.add_resource('sens-Me/',res())
    print "CoAP server started on {}:{}".format(str(host),str(port))
    print self.root.dump()

def main():
    ip = "0.0.0.0"
    port = 5683
    multicast=False
    server = CoAPServer(ip,port,multicast)
    try:
        server.listen(10)
    except KeyboardInterrupt:
        server.close()

if __name__=="__main__":
  main()

服务器运行，我通过copper访问IP地址可以看到。但是当我按下 get 时，我在浏览器上得到了 5.00 Internal Server Error(Blockwise)。有人可以建议我怎么做吗？

Answer 1

首先导入以下内容

from coapthon import defines

然后在 class res 中重新定义 get 函数如下：-

def render_GET(self,request):
   self.payload = (defines.Content_types["application/json"],json.dumps({"e":[{ "n": "temperature", "v":23.5,"u":"degC" }]}))
   return self

使用 CoAPthon 库将 json 有效负载作为 return 值从 CoAP 服务器发送到 GET 方法

Sending a json payload from a CoAP server as return value to GET method using CoAPthon library

python

json

python-2.7

coap