引发异常时，kazoo DataWatch 不会退出程序

Question

我正在使用 kazoo=2.2.1，python 2.7，zookeeper 3.4.5--1。我已经设置了一个 DataWatch，如果回调引发异常，我想中止该程序。我无法使用以下代码中止

from kazoo.recipe.watchers import DataWatch
from utils.zookeeper import Zookeeper
import time
import sys


def do_stuff(data, stat):
   raise NotImplementedError("abort")


def wrap_do_stuff(data, stat):
    try:
        do_stuff(data, stat)
    except Exception as e:
        if data != '':
            print e.message

            # This does not exit the program
            # sys.exit(-1)

            # This does not exit the program
            # raise e

            # This does not exit the program, just stop the watcher
            return False


def start():
    zookeeper_client = Zookeeper.init_from_config().client
    # Someone is writing into this node after creation
    new_node_path = zookeeper_client.create('/test/',
                                        ephemeral=True, sequence=True)
    path_to_watch = new_node_path
    print path_to_watch
    datawatcher = DataWatch(zookeeper_client, path_to_watch, wrap_do_stuff)

    while True:
        time.sleep(2)
        print "still alive"


if __name__ == '__main__':
    start()

`

如何在 wrap_do_stuff() 中中止？

Answer 1

DataWatch 运行在一个单独的线程中，有特定的方法可以从线程中终止主进程，请参阅 Why does sys.exit() not exit when called inside a thread in Python?

类似 os._exit() 的东西确实有效。

引发异常时，kazoo DataWatch 不会退出程序

kazoo DataWatch does not exit the program when exception is raised

python

kazoo

apache-zookeeper