使用特定行拆分 CSV 文件

Question

我想将以下 csv 分成两个 csv

StartOrder,1,SupplierName,
Line,2,12345,2,5,5.50,
Line,3,12345,3,6,5.20,
Line,4,12345,3,7,1.99,
EndOrder,5,booked as soon as possible to deliver.
StartOrder,6,SupplierName
Line,7,100015,2,5,5.50,
Line,8,100015,3,6,5.20,
Line,9,100015,3,7,1.99,
EndOrder,10,booked as soon as possible to deliver.

为了成为：

第一个文件

StartOrder,1,SupplierName,
Line,2,12345,2,5,5.50,
Line,3,12345,3,6,5.20,
Line,4,12345,3,7,1.99,
EndOrder,5,booked as soon as possible to deliver.

第二个文件

StartOrder,6,SupplierName
Line,7,100015,2,5,5.50,
Line,8,100015,3,6,5.20,
Line,9,100015,3,7,1.99,
EndOrder,10,booked as soon as possible to deliver.

我尝试过使用 GroupBy，但没有达到预期效果。

有什么帮助吗？

Answer 1

这是我会用正则表达式做的事情。

    $orders = (get-content -path C:\temp\orders.txt)    
    $orders = [string]::Join("`n",$orders)    # this is to make sure you keep your lines
    $output = [regex]::Matches($orders,'(?s)(StartOrder,(\d{0,}).*?deliver.)') # added regex option S

foreach($c in $output){                
    $order = $c.groups[2].value #order name that will serve as filename
    ""
    $c.groups[0].value # content of order
    $c.groups[0].value  | out-file C:\temp$order.txt -Force
}

这将创建一个 1.txt 和一个包含所需内容的 6.txt。

EDIT ：唯一的问题是它不保留输入。 -> 修复

正则表达式相当简单，关于正则表达式的更多细节：https://regex101.com/r/J0Xsu7/1

这将为您提供 1.txt 和

的文件

StartOrder,1,SupplierName,
Line,2,12345,2,5,5.50,
Line,3,12345,3,6,5.20,
Line,4,12345,3,7,1.99,
EndOrder,5,booked as soon as possible to deliver.

这将为您提供 6.txt 和

的文件

StartOrder,6,SupplierName
Line,7,100015,2,5,5.50,
Line,8,100015,3,6,5.20,
Line,9,100015,3,7,1.99,
EndOrder,10,booked as soon as possible to deliver.

使用特定行拆分 CSV 文件

Split CSV files using a specific line

csv

powershell

powershell-2.0

powershell-3.0