我正在尝试进行反向 URL 调用，但找到了 NOreverse 匹配项

Question

我正在尝试使用反向 URL 在 django 的应用程序（音乐）中调用 URL，但无法调用。下面是我的代码

My main_web_app URL file

    from django.conf.urls import url, include
    from django.contrib import admin


    urlpatterns = [

        url(r'^login$/', include('login.urls')),
        url(r'^admin/', admin.site.urls),
        url(r'^music/', include('Music.urls'), name='indexView')

    ]

我的music/URL文件

    from django.conf.urls import url
    from . import views

    app_name = 'music'

    urlpatterns = [
        # /music/
        url(r'^$', views.IndexView.as_view(), name='indexView'),
        # /music/852
        url(r'^(?P<album_id>[0-9]+)/$', views.DetailView.as_view(), name='detailsView'),
        # /music/add
        url(r'^add/$', views.AddAlbum.as_view(), name='addView')
    ]

我的查看文件

    from django.shortcuts import render
    from django.views import generic
    from django.views.generic.edit import CreateView, UpdateView, DeleteView
    from .models import Album


    class IndexView(generic.ListView):
        template_name = 'Music/index.html'
        context_object_name = 'Album_List'

        def get_queryset(self):
            return Album.objects.all()


    class DetailView(generic.DetailView):
        template_name = 'Music/details.html'
        model = Album


    class AddAlbum(CreateView):
        model = Album
        fields = ['Album_name', 'Artist', 'Genere', 'Album_logo']

我的模板文件

    <!DOCTYPE html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>Title</title>
    </head>
    <body>
        <ul>
        {% for album in Album_List %}
            <li><a href="{% url 'music:detialView' %}">{{ album.Album_name }}
             </a></li>
        {% endfor %}
        </ul>
        <a href="{% url 'music:addView' %}" > Add Album</a>
    </body>
    </html>

出现的错误是

Error during template rendering

In template C:\Users\Varun\Desktop\newsite\Music\templates\Music\index.html, error at line 10
Reverse for 'detailView' not found. 'detailView' is not a valid view function or pattern name.
1   <!DOCTYPE html>
2   <html lang="en">
3   <head>
4       <meta charset="UTF-8">
5       <title>Title</title>
6   </head>
7   <body>
8       <ul>
9       {% for album in Album_List %}
10          <li><a href="{% url 'music:detailView' %}">{{ album.Album_name }}</a></li>
11      {% endfor %}
12      </ul>
13      <a href="{% url 'music:addView' %}" > Add Album</a>
14  </body>
15  </html>

谁能告诉我我做错了什么？？我的应用程序的结构是网站（主要网络应用程序）==> 音乐（包含 1 个模型（专辑））

Answer 1

这里打字错误。将您的 urls.py 更改为：

url(r'^(?P<album_id>[0-9]+)/$', views.DetailView.as_view(), name='detailView'),

注意 detailsView 里面的额外 s。

我正在尝试进行反向 URL 调用，但找到了 NOreverse 匹配项

I am trying to make a reverse URL call but getting NOreverse match found

python

django

url

django-urls