基于值的值选择的字符串

Question

我有一个包含 2 个值的集合

list = [('coin unit', 9.0), ('normal margin requirements', 8.5), ('futures industry', 8.2), ('wild cryptocurrency market', 7.333333333333334), ('biggest financial institutions', 6.833333333333334), ('futures market', 1.0), ('biggest banks', 0.5), ('cryptocurrency frenzy', 0.5)]

如何只保留分数大于 1 的值？

Answer 1

list_of_stuff = [('coin unit', 9.0), ('normal margin requirements', 8.5), ('futures industry', 8.2), ('wild cryptocurrency market', 7.333333333333334), ('biggest financial institutions', 6.833333333333334), ('futures market', 1.0), ('biggest banks', 0.5), ('cryptocurrency frenzy', 0.5)]
newlist = [x for x in list_of_stuff if x[1] > 1.0]
print newlist

将导致

[('coin unit', 9.0), ('normal margin requirements', 8.5), ('futures industry', 8.2), ('wild cryptocurrency market', 7.333333333333334), ('biggest financial institutions', 6.833333333333334)]

Answer 2

What about without loop :

list_1 = [('coin unit', 9.0), ('normal margin requirements', 8.5), ('futures industry', 8.2), ('wild cryptocurrency market', 7.333333333333334), ('biggest financial institutions', 6.833333333333334), ('futures market', 1.0), ('biggest banks', 0.5), ('cryptocurrency frenzy', 0.5)]

print(list(filter(lambda x:x[1]>1,list_1)))

输出：

[('coin unit', 9.0), ('normal margin requirements', 8.5), ('futures industry', 8.2), ('wild cryptocurrency market', 7.333333333333334), ('biggest financial institutions', 6.833333333333334)]

P.S ：永远不要使用 list 作为变量名，因为 list 是 python.

中的关键字

基于值的值选择的字符串

string with values selection based on values

python

list

selection