Oracle 中的 Union null
Union null in Oracle
我正在尝试在 oracle 中组合 2 个查询,这些行具有相同的值,除了一个字段。
例如:
SELECT NAME, AGE, EMAIL, DATE FROM table_a WHERE NAME = 'JOAO' AND FLAG = '0'
UNION
SELECT NAME, AGE, EMAIL, DATE FROM table_a WHERE NAME = 'JOAO' AND FLAG = '1'
结果:
NAME AGE EMAIL DATE
JOAO 23 a@a.com 20150414
JOAO 23 a@a.com null
如何将这些行分组??我正在寻找可以给我这样结果的人:
NAME AGE EMAIL DATE
JOAO 23 a@a.com 20150414
谢谢
(对不起我的英语..)
如果您只是想忽略 NULL 值:
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG in ( '0', '1' )
and date is not null
/
或
如果您想保留空值,但要遵循可用的非空值:
with w_data as (
SELECT NAME, AGE, EMAIL, DATE ,
row_number() over ( partition by name
order by date desc nulls last ) rnum
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG in ( '0', '1' )
)
select name, age, email, date
from w_data
where rnum = 1
/
[编辑]
回复评论:
如果你想保持并集,那很好,并集和 OR 大部分是可以互换的(在这种情况下):
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '0'
and date is not null
union
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '1'
and date is not null
/
甚至:
select * from (
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '0'
union
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '1'
)
where date is not null
/
如果您只想在 1 个地方使用 NULL 条件;)
同样的逻辑可以适用于我在上面使用 row_number() analytics 编写的第二个查询 ...
with w_data as (
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '0'
union
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '1'
),
w_sub as (
select name, age, email, date,
row_number() over ( partition by name
order by date desc nulls last ) rnum
from w_data
)
select name, age, email, date
from w_sub
where rnum = 1
/
将 'WHERE' 子句中的条件从
更改为这种情况
WHERE NAME = 'JOAO' AND FLAG = '0'
至
WHERE NAME = 'JOAO' AND FLAG IN('0','1')
因此您的选择显示了列 'FLAG'.
的所有寄存器的值为“0”或“1”
您可以使用 COALESCE()。 http://docs.oracle.com/cd/B28359_01/server.111/b28286/functions023.htm#SQLRF00617/ms190349.aspx
这个查询应该适用于每个名字,并且应该合并其他行。
SELECT
NAME1 AS NAME,
COALESCE(AGE1, AGE2) AS AGE,
COALESCE(EMAIL1, EMAIL2) AS EMAIL,
COALESCE(DATE1, DATE2) AS DATE
FROM(
SELECT
t1.NAME AS NAME1,
t1.AGE AS AGE1,
t1.EMAIL AS EMAIL1,
t1.DATE AS DATE1,
t2.NAME AS NAME2,
t2.AGE AS AGE2,
t2.EMAIL AS EMAIL2,
t2.DATE AS DATE2
FROM table_a AS t1
INNER JOIN table_a AS t2
ON t2.FLAG = 1 AND t1.FLAG = 0 AND t1.NAME = t2.NAME
) AS t3;
我正在尝试在 oracle 中组合 2 个查询,这些行具有相同的值,除了一个字段。
例如:
SELECT NAME, AGE, EMAIL, DATE FROM table_a WHERE NAME = 'JOAO' AND FLAG = '0'
UNION
SELECT NAME, AGE, EMAIL, DATE FROM table_a WHERE NAME = 'JOAO' AND FLAG = '1'
结果:
NAME AGE EMAIL DATE
JOAO 23 a@a.com 20150414
JOAO 23 a@a.com null
如何将这些行分组??我正在寻找可以给我这样结果的人:
NAME AGE EMAIL DATE
JOAO 23 a@a.com 20150414
谢谢 (对不起我的英语..)
如果您只是想忽略 NULL 值:
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG in ( '0', '1' )
and date is not null
/
或 如果您想保留空值,但要遵循可用的非空值:
with w_data as (
SELECT NAME, AGE, EMAIL, DATE ,
row_number() over ( partition by name
order by date desc nulls last ) rnum
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG in ( '0', '1' )
)
select name, age, email, date
from w_data
where rnum = 1
/
[编辑] 回复评论:
如果你想保持并集,那很好,并集和 OR 大部分是可以互换的(在这种情况下):
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '0'
and date is not null
union
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '1'
and date is not null
/
甚至:
select * from (
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '0'
union
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '1'
)
where date is not null
/
如果您只想在 1 个地方使用 NULL 条件;) 同样的逻辑可以适用于我在上面使用 row_number() analytics 编写的第二个查询 ...
with w_data as (
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '0'
union
SELECT NAME, AGE, EMAIL, DATE
FROM table_a
WHERE NAME = 'JOAO'
AND FLAG = '1'
),
w_sub as (
select name, age, email, date,
row_number() over ( partition by name
order by date desc nulls last ) rnum
from w_data
)
select name, age, email, date
from w_sub
where rnum = 1
/
将 'WHERE' 子句中的条件从
更改为这种情况WHERE NAME = 'JOAO' AND FLAG = '0'
至
WHERE NAME = 'JOAO' AND FLAG IN('0','1')
因此您的选择显示了列 'FLAG'.
的所有寄存器的值为“0”或“1”您可以使用 COALESCE()。 http://docs.oracle.com/cd/B28359_01/server.111/b28286/functions023.htm#SQLRF00617/ms190349.aspx
这个查询应该适用于每个名字,并且应该合并其他行。
SELECT
NAME1 AS NAME,
COALESCE(AGE1, AGE2) AS AGE,
COALESCE(EMAIL1, EMAIL2) AS EMAIL,
COALESCE(DATE1, DATE2) AS DATE
FROM(
SELECT
t1.NAME AS NAME1,
t1.AGE AS AGE1,
t1.EMAIL AS EMAIL1,
t1.DATE AS DATE1,
t2.NAME AS NAME2,
t2.AGE AS AGE2,
t2.EMAIL AS EMAIL2,
t2.DATE AS DATE2
FROM table_a AS t1
INNER JOIN table_a AS t2
ON t2.FLAG = 1 AND t1.FLAG = 0 AND t1.NAME = t2.NAME
) AS t3;