用于反序列化以分号分隔的字符串的正则表达式

Question

我有一个具有以下格式的字符串：-

"{\"A5\";\"A6\";\"A7\";\"varying number of params...\"}"

如何使用PHP将字符串转换成 A5, A6, A7, varying number of params...

我知道 str_replace 是一种方法，但我想知道使用正则表达式是否更好？

Answer 1

(?<=\")[^\;]+

尝试 this.See 演示。

https://regex101.com/r/sH8aR8/53

$re = "/(?<=\\\")[^\\;]+/";
$str = "\"{\"A5\";\"A6\";\"A7\";\"varying number of params...\"}\"";

preg_match_all($re, $str, $matches);

详情：

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  (?<=                     look behind to see if there is:
--------------------------------------------------------------------------------
    \                       '\' 
--------------------------------------------------------------------------------
    "                        '"'
--------------------------------------------------------------------------------
  )                        end of look-behind
--------------------------------------------------------------------------------
  [^\;]+                  any character except: '\', ';' (1 or more
                       times (matching the most amount possible))

Answer 2

如果您不需要正则表达式的强大功能，您也可以将 str_replace 与数组一起使用：

echo str_replace(array('"{\"', '\";\"', '\"}"'), array("", ", ", ""), $str);

-> A5, A6, A7, varying number of params... test at eval.in

用于反序列化以分号分隔的字符串的正则表达式

Regex for deserializing string separated by semi-colon

php

regex