python 从 RGB 元组创建图像

Question

我有一个包含如下图像数据的多行 .txt 文件：

(198, 252, 247) (255, 255, 250) (254, 253, 248) (251, 252, 246) (247, 248, 240) ... 
(100, 144, 247) (255, 200, 250) (254, 253, 248) (251, 252, 246) (247, 248, 240) ...

如何将这些数据读入元组？

lst = [((198, 252, 247), (255, 255, 250)), (second line), (thrid) ...]

并最终使用 Image 模块将每一行绘制回图像文件

Answer 1

简单地读取每一行，从中提取值三元组，并将它们转换为整数。

import re

triplet = r'\((\d+), (\d+), (\d+)\)' # regex pattern

image = []
with open('image.txt') as fp:
    for line in fp:
        image.append([(int(x), int(y), int(z)) for x, y, z in re.findall(triplet, line)])

编辑

要实际绘制图像，请查看 this question。但是，这应该有效：

from PIL import Image

width, height = len(image[0]), len(image)
data = sum(image, []) # ugly hack to flatten the image

im = Image.new('RGB', (width, height))
im.putdata(data)
im.save('image.png')

Answer 2

首先你需要从文件中扫描和拆分数据，然后你可以从数据中解析出元组（字符串元组），然后简单地使用PIL创建一个图像对象

def getTuple(s):
    try:
        s = eval(str(s))
        if type(s) == tuple:
            return s
        return
    except:
        return

with open("filename.txt", "rb") as fp:
    im_list = []
    data_points = fp.read()
    data_point_list = data_points.split("-")
    for data_point in data_point_list:
        im_list.append(getTuple(data_point))
    # the code snippet from 
    im2 = Image.new(im.mode, im.size)
    im2.putdata(list_of_pixels)

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