Python Latin-1 对十进制的补充

Question

和python

ord('a')

给予

但是

ord('é')

报错

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: ord() expected a character, but string of length 2 found

如何像 https://en.wikipedia.org/wiki/List_of_Unicode_characters#Latin-1_Supplement 那样获取除 ASCII (é = 233) 以外的其他字母的小数点？

Answer 1

你可以先解码：

ord('é'.decode('utf-8'))  # outputs 233

Python Latin-1 Supplement to decimal