Laravel : 如何从数据库中搜索多个值

Question

在我的搜索中有 $categroy_id - $country_id - $city_id。有一个 table activities 具有所有这些值。

我只是在我的控制器中实现了一个功能，但它 return 所有数据。

我的控制器功能码：

public function PlanActivity(Request $request){
    $category_id = $request->category_id;
    $countryid = $request->country_id;
    $cityid = $request->city_id;
    $listactivity = Activity::all(); // get all activity
    if($category_id != '') {
        $listactivity->where('category_id', function ($query) use ($category_id) {
            $query->where('category_id', $category_id);
        });
    }

    return view('front.plan_activity',compact('listactivity'));
}

我该怎么做？

Answer 1

使用多个 where 子句：

查询生成器

// match any one of the values
$activities = DB::table('activities')->where('category_id', $category_id)
                       ->orWhere('country_id', $country_id)
                       ->orWhere('city_id', $city_id)
                       ->get();

// match all of the values
$activities = DB::table('activities')->where('category_id', $category_id)
                       ->where('country_id', $country_id)
                       ->where('city_id', $city_id)
                       ->get();

Eloquent

// match any one of the values
$activities = Activity::where('category_id', $category_id)
                       ->orWhere('country_id', $country_id)
                       ->orWhere('city_id', $city_id)
                       ->get();

// match all of the values
$activities = Activity::where('category_id', $category_id)
                       ->where('country_id', $country_id)
                       ->where('city_id', $city_id)
                       ->get();

// this can be merged together in one array
$activities = Activity::where([
     'category_id' => $category_id,
     'country_id' => $country_id,
     'city_id' => $city_id
])->get();

如果请求参数为空

public function PlanActivity(Request $request){
    if (!$categroy_id && !$country_id && !$city_id) {
        $activities = Activity::all();
    } else {
        // do the above queries
    }

    return view('front.plan_activity',compact('activities'));
}

Answer 2

您的错误在于使用了 Laravel 模型提供的 eloquent 功能。当您调用 all() 函数时，它基本上会将 SELECT * FROM 您的 table 和 returns 结果作为一个对象。如果您需要过滤此查询或添加任何内容，您将不再使用 all()，而是使用 get() 作为最后一个函数。

至于在模型上设置此查询，您已经在模型中了！当您调用 Activity::whatever-function-next() 时，您就在模型内部，而 Laravel 已经为您提供了所有这些功能，可以轻松创建查询。第一个答案给了你所有你需要的，只要确保理解这些函数和类实际在做什么。

Answer 3

您可以使用此查询进行搜索，

public function PlanActivity(Request $request)
{
    $category_id = $request->category_id;
    $country_id = $request->country_id;
    $city_id = $request->city_id;
    $activity = new Activity; // get all activity
    $search = $activity->search();
    if($category_id) {
       $search->where('category_id', $category_id);
    }
    if($country_id){
       $search->where('country_id', $country_id);
    }
    if($city_id){
      $search->where('city_id', $city_id);
    }


    $listactivity = $search->

    return view('front.plan_activity',compact('listactivity'));
}

Answer 4

首先，您需要为 activity table 创建一个模型。

class Activity extends Model
{
    protected $table = 'activities'; //table name
    protected $guarded = [];
}

然后你可以像他上面说的那样写查询

$activities = Activity::where('category_id', $category_id)
                           ->orWhere('country_id', $country_id)
                           ->orWhere('city_id', $city_id)
                           ->get();

Laravel : 如何从数据库中搜索多个值

Laravel : how to search multiple value from database

laravel

laravel-5.5