读取文件并查找是否存在字符串和 return 表名

Question

我正在尝试读取一个文件，如果文件有 'alter table' 那么它必须搜索 'modify' 如果修改存在那么它必须 return table 姓名。为此，我编写了以下代码并且它有效。

filename='modify_table.sql'
bol1="false"
File.foreach(filename).with_index do |line, line_num|

#convert all characters to upper case
 if ( line =~ /[a-z]/ )
 line = line.upcase
 end
  if (line =~ /ALTER TABLE/) 

    location = line.index("ALTER TABLE") + 11
    subline = line[location..-1]
    sublineParts = subline.split(" ")
    tableName = sublineParts[0]

    bol1 = line.include?("MODIFY")
    if (bol1)
    puts " found modify column on #{tableName}"
  else
    puts " no modify found"
  end
end
end

我的文件包含：

begin
BEGIN EXECUTE IMMEDIATE 'alter table schemaname.tablename 
modify (
abc              VARCHAR2(200 BYTE),
xyz               VARCHAR2(200 BYTE)
)'; EXCEPTION when others then if (SQLCODE != -01430 and SQLCODE != -942) then RAISE; end if; END;
end;
/

如果更改和修改在同一行，我的代码就可以工作。在上面的文件中，两者都在差异行中。所以我写的代码 returns 没有找到修改，即使文件中有修改。有人可以帮助我如何阅读下一行并找到 modify

Answer 1

这不是解决问题的最佳方法。但是这段代码会让它工作。

filename='modify_table.sql'
bol1 = false
lookformodify = false
tableName = ''
File.foreach(filename).with_index do |line, line_num|
  # convert all characters to upper case
  line = line.upcase if line =~ /[a-z]/
  if !lookformodify && line =~ /ALTER TABLE/
    lookformodify = true

    location = line.index('ALTER TABLE') + 11
    subline = line[location..-1]
    sublineParts = subline.split(' ')
    tableName = sublineParts[0]

    bol1 = line.include?('MODIFY')
    if bol1
      puts " found modify column on #{tableName}"
      lookformodify = false # found on same line. No need to look on other lines
    end
  elsif lookformodify && line =~ /MODIFY/
    puts " found modify column on #{tableName}"
    lookformodify = false # found on different line. No need to look on other lines
  end
end

读取文件并查找是否存在字符串和 return 表名

read a file and find if a string exists and return the tablename

ruby

ruby-on-rails-3