Laravel过滤结果，已经过滤的

Question

我在这里获取可用的交易：

$buildQuery = Deals::with(['market:id,name','propertyType:id,name','dealStatus:id,name']);

        if($request->filled('property_type')){
            $buildQuery->where('property_type_id', $request->property_type);
        }

        if($request->filled('purchase_price')){

            $price = explode("-",$request->purchase_price);
            $min_price = (int)$price[0];
            $max_price = (int)$price[1];

            $buildQuery->whereBetween('purchase_price', [$min_price, $max_price]);
        }


        if($request->filled('status')){
            $buildQuery->where('status', $request->status);
        }



        $getDeals = $buildQuery->whereIn('deal_status_id',$dealStatua)
                                ->whereIn('market_id',$getMarket)
                                ->orderBy('id')->get();

我的问题是当用户选择 'estimated_profit' 列时，我想进行一些手动计算，如果它与所选值匹配，则什么都不做 remove that row from $getDeals 变量，

        if($request->filled('estimated_profit')){
            foreach($getDeals as $row){
                $deal = Deal::find($row->id);

                $purchase_price = $deal->purchase_price;
                $cost_of_price = $deal->cost_of_price;
                $arv_price = $deal->arv_price;

                $calculated_estimated_profit = $arv_price - ( $purchase_price + $cost_of_price );

                $price = explode("-",$request->estimated_profit);
                $min_price = (int)$price[0];
                $max_price = (int)$price[1];

                if($calculated_estimated_profit >= $min_price && $calculated_estimated_profit <= $max_price){
                    // dont do anything here
                }else{
                    // dont want that row here
                }

            }
        }

Answer 1

你试试这个：$getDeals->forget($row) 如果它不起作用，你可以尝试获取 $row 索引和 $getDeals->forget($index) ！其他信息看这里：

Laravel过滤结果，已经过滤的

Laravel filter the result, that are already filtered

php

mysql

laravel

laravel-5.5