MYSQL 数据库 SELECT 带最小计数
MYSQL DB SELECT WITH MIN COUNT
我得到了一个数据集 table 它看起来像这样:
###################################
UID |TID |MID |RESULT |
1 |1 |1 |1 |
2 |1 |1 |2 |
3 |1 |1 |3 |
4 |2 |1 |4 |
5 |2 |1 |5 |
6 |2 |1 |6 |
1 |1 |2 |6 |
2 |1 |2 |5 |
3 |1 |2 |4 |
4 |2 |2 |3 |
5 |2 |2 |2 |
6 |2 |2 |1 |
1 |1 |3 |2 |
2 |1 |3 |4 |
3 |1 |3 |6 |
4 |2 |3 |5 |
5 |2 |3 |3 |
6 |2 |3 |1 |
我现在想要每行的最小数量,按 TID 和 MID 分组
如果我这样做:
SELECT UID, TID, MID, RESULT
FROM matches
WHERE matches.id = '$ID'
ORDER BY TID, MID, RESULT
我以正确的方式订购了东西。像这样:
###################################
UID |TID |MID |RESULT |
1 |1 |1 |1 |
2 |1 |1 |2 |
3 |1 |1 |3 |
3 |1 |2 |4 |
2 |1 |2 |5 |
1 |1 |2 |6 |
1 |1 |3 |2 |
2 |1 |3 |4 |
3 |1 |3 |6 |
4 |2 |1 |4 |
5 |2 |1 |5 |
6 |2 |1 |6 |
6 |2 |2 |1 |
5 |2 |2 |2 |
4 |2 |2 |3 |
6 |2 |3 |1 |
5 |2 |3 |3 |
4 |2 |3 |5 |
我现在只想拥有每个块的第一行。统计每个块中每个 UID 的最佳频率。
我不知道如何在 php 中不做很多循环就得到它。如果我按 TID、MID 和 MIN(RESULT) 进行 GROUP BY TID,它会随机出现哪个 UID。
解决方案:
SELECT COUNT(*) AS AMOUNT, t1.UID AS UID, t1.TID AS TID, t1.MID AS MID, t1.RESULT AS result
FROM
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, um.q_result AS RESULT
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
ORDER BY TID, MID
) t1
INNER JOIN
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, min(um.q_result) AS min_result
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
GROUP BY TID, MID
) t2 ON t2.TID = t1.TID AND t2.MID = t1.MID AND t2.min_result = t1.result
GROUP BY t1.UID ORDER BY AMOUNT DESC
您可以将子查询与按 TID 和 MID 的列结果组的最小值一起使用
SELECT UID, TID, MID, RESULT
FROM matches m
inner join (
select TID, MID, min(result) min_result
from matches
group by TID, MID
) t on t.TID = m.TID and t.MID = m.MID and t.min_result = m.result
查看您的代码和示例,您在子选择中有一个错误 user_id,您没有分组依据而是排序依据,所以我认为您应该这样更改代码
SELECT COUNT(*) AS AMOUNT, t1.UID AS UID, t1.TID AS TID, t1.MID AS MID, t1.RESULT AS result
FROM
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, um.q_result AS RESULT
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
ORDER BY TID, MID
) t1
INNER JOIN
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, min(um.q_result) AS min_result
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
GROUP BY TID, MID
) t2 ON t2.TID = t1.TID AND t2.MID = t1.MID AND t2.min_result = t1.result
GROUP BY t1.UID ORDER BY AMOUNT DESC
我得到了一个数据集 table 它看起来像这样:
###################################
UID |TID |MID |RESULT |
1 |1 |1 |1 |
2 |1 |1 |2 |
3 |1 |1 |3 |
4 |2 |1 |4 |
5 |2 |1 |5 |
6 |2 |1 |6 |
1 |1 |2 |6 |
2 |1 |2 |5 |
3 |1 |2 |4 |
4 |2 |2 |3 |
5 |2 |2 |2 |
6 |2 |2 |1 |
1 |1 |3 |2 |
2 |1 |3 |4 |
3 |1 |3 |6 |
4 |2 |3 |5 |
5 |2 |3 |3 |
6 |2 |3 |1 |
我现在想要每行的最小数量,按 TID 和 MID 分组
如果我这样做:
SELECT UID, TID, MID, RESULT
FROM matches
WHERE matches.id = '$ID'
ORDER BY TID, MID, RESULT
我以正确的方式订购了东西。像这样:
###################################
UID |TID |MID |RESULT |
1 |1 |1 |1 |
2 |1 |1 |2 |
3 |1 |1 |3 |
3 |1 |2 |4 |
2 |1 |2 |5 |
1 |1 |2 |6 |
1 |1 |3 |2 |
2 |1 |3 |4 |
3 |1 |3 |6 |
4 |2 |1 |4 |
5 |2 |1 |5 |
6 |2 |1 |6 |
6 |2 |2 |1 |
5 |2 |2 |2 |
4 |2 |2 |3 |
6 |2 |3 |1 |
5 |2 |3 |3 |
4 |2 |3 |5 |
我现在只想拥有每个块的第一行。统计每个块中每个 UID 的最佳频率。
我不知道如何在 php 中不做很多循环就得到它。如果我按 TID、MID 和 MIN(RESULT) 进行 GROUP BY TID,它会随机出现哪个 UID。
解决方案:
SELECT COUNT(*) AS AMOUNT, t1.UID AS UID, t1.TID AS TID, t1.MID AS MID, t1.RESULT AS result
FROM
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, um.q_result AS RESULT
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
ORDER BY TID, MID
) t1
INNER JOIN
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, min(um.q_result) AS min_result
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
GROUP BY TID, MID
) t2 ON t2.TID = t1.TID AND t2.MID = t1.MID AND t2.min_result = t1.result
GROUP BY t1.UID ORDER BY AMOUNT DESC
您可以将子查询与按 TID 和 MID 的列结果组的最小值一起使用
SELECT UID, TID, MID, RESULT
FROM matches m
inner join (
select TID, MID, min(result) min_result
from matches
group by TID, MID
) t on t.TID = m.TID and t.MID = m.MID and t.min_result = m.result
查看您的代码和示例,您在子选择中有一个错误 user_id,您没有分组依据而是排序依据,所以我认为您应该这样更改代码
SELECT COUNT(*) AS AMOUNT, t1.UID AS UID, t1.TID AS TID, t1.MID AS MID, t1.RESULT AS result
FROM
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, um.q_result AS RESULT
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
ORDER BY TID, MID
) t1
INNER JOIN
(
SELECT um.user_id AS UID, um.team_id AS TID, um.match_id AS MID, min(um.q_result) AS min_result
FROM user_matches um JOIN league_matches lm
WHERE um.match_id = lm.id
AND lm.league_subseason_id = '135'
GROUP BY TID, MID
) t2 ON t2.TID = t1.TID AND t2.MID = t1.MID AND t2.min_result = t1.result
GROUP BY t1.UID ORDER BY AMOUNT DESC