如何使用 PHP 从数组中插入多个 POST 值

Question

这是我的代码，当我回显它显示所有 POST 数组时，但是当 mysqli_query 操作运行它只插入最后一个值。如何在查询中插入所有数据？谁能帮帮我...

$ser = $_POST['serial'];
foreach ($ser as $seria) {
    echo $serial = $seria;
}

$re = $_POST['ref_no'];
foreach ($re as $refe) {
    echo $ref = $refe;
}

$des = $_POST['desc'];  
foreach ($des as $desce) {
    echo $desc = $desce;
}

$uni = $_POST['unitss'];
foreach ($uni as $units) {
    echo $unit = $units;
}

$qt = $_POST['qty'];
foreach ($qt as $qtys) {
    echo $qty = $qtys;
}

$pric = $_POST['price'];
foreach ($pric as $prices) {
    echo $price = $prices;
}

$amoun = $_POST['amount'];
foreach ($amoun as $amounts) {
    echo $amount = $amounts;
}

mysqli_query($con, "INSERT into purchase_order (po_id, po_no, serial_no, ref_no, description, unit, qty, price, amount, status) VALUES ('', '".$po_nom."', '".$mr_no."', '".$serial."', '".$ref."', '".$desc."', '".$unit."', '".$qty."', '".$price."', '".$amount."', 'Pending')");

Answer 1

试试这个

$serial = $_POST['serial'];
$ref = $_POST['ref_no'];
$desc = $_POST['desc'];  
$unit = $_POST['unitss'];
$qty = $_POST['qty'];
$price = $_POST['price'];
$amount = $_POST['amount'];

mysqli_query($con, "INSERT into purchase_order (po_id, po_no, serial_no, ref_no, description, unit, qty, price, amount, status) VALUES ('', '".$po_nom."', '".$mr_no."', '".$serial."', '".$ref."', '".$desc."', '".$unit."', '".$qty."', '".$price."', '".$amount."', 'Pending')");

Answer 2

这里有一个相当大的假设，即所有数组都具有相同的大小：

$sql='';
$n=len($_POST['serial']);
for ($i=0;$i<$n;$i++) {
    $amount = $_POST['amount'][$i];
    $price = $_POST['price'][$i];
    $qty=$_POST['qty'][$i];
    $unit=$_POST['unitss'][$i];
    $desc=$_POST['desc'][$i];
    $ref=$_POST['ref_no'][$i];
    $serial=$_POST['serial'][$i];
    $sql_part="INSERT into purchase_order (po_id, po_no, serial_no, ref_no, description, unit, qty, price, amount, status) VALUES ('', '".$po_nom."', '".$mr_no."', '".$serial."', '".$ref."', '".$desc."', '".$unit."', '".$qty."', '".$price."', '".$amount."', 'Pending')";
    $sql=$sql.';'.$sql_part;
}
mysqli_query($con, $sql);

另外请注意，由于 SQL injections

，直接从 $_POST 变量将数据插入数据库并不是一个好习惯

Answer 3

试试这个

$ser = $_POST['serial'];
foreach($ser as $keys=>$vals){
mysqli_query($con, "INSERT into purchase_order (po_id, serial_no, ref_no, description, unit, qty, price, amount, status) VALUES ('', '".$vals."', '".$_POST['ref'][$keys]."', '".$_POST['desc'][$keys]."', '".$_POST['unitss'][$keys]."', '".$_POST['qty'][$keys]."', '".$_POST['price'][$keys]."', '".$_POST['amount'][$keys]."', 'Pending')");
}

或者你也可以这样做

$ser = $_POST['serial'];
foreach($ser as $keys=>$vals){
$values_array[]="('', '".$vals."', '".$_POST['ref'][$keys]."', '".$_POST['desc'][$keys]."', '".$_POST['unitss'][$keys]."', '".$_POST['qty'][$keys]."', '".$_POST['price'][$keys]."', '".$_POST['amount'][$keys]."', 'Pending')";

}
$values=implode(",",$values_array);
mysqli_query($con, "INSERT into purchase_order (po_id, serial_no, ref_no, description, unit, qty, price, amount, status) VALUES ".$values." ");

Answer 4

您的回声显示所有值的原因是它们每个都在您正在运行遍历数组的循环中。你正在做的是在每次循环时覆盖循环内每个变量的值，回显它，然后用数组中的下一个值再次覆盖它。

如果所有数组的大小都相同，您将只能做您想做的事情，然后您需要在循环内而不是在循环之后构建查询字符串。

我不熟悉 mysqli，所以我会给你一个使用 PDO 的例子（这是未经测试的，并不意味着只是插入你的代码，它只是为了让逻辑和过程更清晰） :

$con= new PDO("mysql:host=<host>;dbname=<dbName>", "dbUsr", "dbPwd");
$sql = "INSERT INTO purchase_order (po_id, po_no, serial_no, ref_no, description, unit, qty, price, amount, status) VALUES";
$masterArray = [];
for($i = 0; $i < count($_POST['serial']); $i++){
  $masterArray[] = array('serial=>$_POST['serial'], 'ref_no'=>$_POST['ref_no'], 'desc'=>$_POST['desc'], 'unitss'=>$_POST['unitss'], 'qty'=>$_POST['qty'], 'price'=>$_POST['price'], 'amount'=>$_POST['amount'])
  $sql .= "(?,?,?,?,?,?,?,?,?,"Pending") ";
}
$stmt = $con->prepare($sql);
$marker = 1;
foreach($masterArray as $idx=>$row){
  foreach($row as $title=>$value){
    $stmt->bindParam($marker, $value)
    $marker++;
  }
}
$stmt->execute();

如何使用 PHP 从数组中插入多个 POST 值

How to insert mulitple POST value from array using PHP

php

mysqli