使用赋值运算符重载时，无法在 operator=() 之外访问新对象

Question

我有一个 Queue 的实现，它需要编写赋值运算符重载。

Queue& Queue::operator= (const Queue& rhs){
  if(this->head == rhs.head) return *this;

  Queue * newlist;
  if(rhs.head == NULL){ 
    // copying over an empty list will clear it.
    this->clear();
    return * newlist;
  }

  newlist = new Queue(rhs);
  cout << "made new queue" << endl;

  cout << "new list : " << * newlist << endl;
  return * newlist;
}

我运行遇到的问题是，当我离开这个函数时， newlist 的内容将无法再访问。 operator=() 函数应该是什么样子？

编辑： queue.h:

class Queue : public LinkedList {
protected:
    unsigned maxSize;

public:
    Queue(unsigned N = -1);
    Queue(const Collection& collection, unsigned N = -1);
    ~Queue();
    Queue(const Queue& obj);
    Queue& operator= (const Queue& rhs);
    friend std::ostream& operator<<(std::ostream& ostream, const Queue &rhs);
    bool add(myType element);
    myType element();
    bool offer(myType element);
    myType peek();
    myType poll();
    myType remove();

};

Answer 1

How is an operator=() function supposed to look?

operator= 应该用 rhs 的值修改内部对象 (*this)，然后按字面意思 return (*this).

使用赋值运算符重载时，无法在 operator=() 之外访问新对象

When using assignment operator overloading, the new object isn't accessible outside of operator=()

c++

operator-overloading