使用 oracle 中的存储过程更新 table
update a table using a stored procedure in oracle
我有一个 table t_time,其中我有以下属性
time_key, calendar_dt, cal_year, cal_quarter, cal_month, cal_week, week_in_month, cal_st_dt_of_wk, cal_end_dt_of_wk, rfrsh_dt, cal_yyyymm
select * from t_time where time_key = (select max(time_key) from t_time);
74937 31-12-2015 2015 4 12 5 5 27-12-2015 02-01-2016 17-07-2009 201512
我想编写一个存储过程,这样当我指定年份时,t_time 应该与所有键和其他属性一起插入..
喜欢
2016 年
time_key calendar_dt cal_year cal_quarter cal_month cal_week week_in_month cal_st_dt_of_wk cal_end_dt_of_wk rfrsh_dt cal_yyyymm
74938 01-01-2016 2016 1 1 1 1 01-01-2016 02-01-2016 22-04-2015 201601
74939 02-01-2016 2016 1 1 1 1 01-01-2016 02-01-2016 22-04-2015 201601
74940 03-01-2016 2016 1 1 2 2 03-01-2016 09-01-2016 22-04-2015 201601
74941 04-01-2016 2016 1 1 2 2 03-01-2016 09-01-2016 22-04-2015 201601
cal_end_dt_of_wk 是那个星期的星期六
cal_st_dt_of_wk 是那个星期的星期日
谁能给我一个开始的想法..
time_key - time_key + 1
calendar_dt - select sysdate from dual;
cal_year - select extract(year from sysdate) from dual;
cal_quarter - select case when extract(month from sysdate) in (1,2,3) then 1
case when extract(month from sysdate) in (4,5,6) then 2
case when extract(month from sysdate) in (7,8,9) then 3
case when extract(month from sysdate) in (10,11,12) then 4 else 0 end as cal_quarter from dual;
cal_month - select extract(month from sysdate) from dual;
cal_week - select to_char(to_date(sysdate),'ww') from dual;
week_in_month - select to_char(to_date(sysdate),'w') from dual;
cal_st_dt_of_wk - select trunc(sysdate,'iw')-1 from dual;
cal_end_dt_of_wk - select trunc(sysdate,'iw')+5 from dual;
rfrsh_dt - select sysdate from dual;
cal_yyyymm - select to_char(sysdate,'yyyymm') from dual;
好的,内容很多 ;) 但我认为这现在应该可以了:
-- provide year as YYYY
CREATE OR REPLACE PROCEDURE fill_table (year IN VARCHAR2) IS
date_holder DATE := TO_DATE ('01.01.' || year,'DD.MM.YYYY');
BEGIN
WHILE (TO_CHAR (date_holder,'YYYY') = year) LOOP
INSERT INTO t_time
VALUES (1,
date_holder,
extract(year from date_holder),
case when extract(month from date_holder) in (1,2,3) then 1
when extract(month from date_holder) in (4,5,6) then 2
when extract(month from date_holder) in (7,8,9) then 3
when extract(month from date_holder) in (10,11,12) then 4 else 0 END,
extract(month from date_holder),
to_char(to_date(date_holder),'ww'),
to_char(to_date(date_holder),'w'),
trunc(date_holder,'iw')-1,
trunc(date_holder,'iw')+5,
sysdate ,
to_char(date_holder,'yyyymm'));
date_holder := date_holder +1;
END LOOP;
END;
/
所以基本思路是:
- 从
1.1.<YEAR>
日期开始
- 一天一天相加并按照您的描述插入值
日历周、月中周、周的开始和结束似乎有问题......无论如何 - 这种方法应该没问题。我也省略了正确的密钥计算 - 最好的选择是 SEQUENCE
.
p.s.: 检查this demo.
我有一个 table t_time,其中我有以下属性
time_key, calendar_dt, cal_year, cal_quarter, cal_month, cal_week, week_in_month, cal_st_dt_of_wk, cal_end_dt_of_wk, rfrsh_dt, cal_yyyymm
select * from t_time where time_key = (select max(time_key) from t_time);
74937 31-12-2015 2015 4 12 5 5 27-12-2015 02-01-2016 17-07-2009 201512
我想编写一个存储过程,这样当我指定年份时,t_time 应该与所有键和其他属性一起插入..
喜欢
2016 年
time_key calendar_dt cal_year cal_quarter cal_month cal_week week_in_month cal_st_dt_of_wk cal_end_dt_of_wk rfrsh_dt cal_yyyymm
74938 01-01-2016 2016 1 1 1 1 01-01-2016 02-01-2016 22-04-2015 201601
74939 02-01-2016 2016 1 1 1 1 01-01-2016 02-01-2016 22-04-2015 201601
74940 03-01-2016 2016 1 1 2 2 03-01-2016 09-01-2016 22-04-2015 201601
74941 04-01-2016 2016 1 1 2 2 03-01-2016 09-01-2016 22-04-2015 201601
cal_end_dt_of_wk 是那个星期的星期六 cal_st_dt_of_wk 是那个星期的星期日
谁能给我一个开始的想法..
time_key - time_key + 1
calendar_dt - select sysdate from dual;
cal_year - select extract(year from sysdate) from dual;
cal_quarter - select case when extract(month from sysdate) in (1,2,3) then 1
case when extract(month from sysdate) in (4,5,6) then 2
case when extract(month from sysdate) in (7,8,9) then 3
case when extract(month from sysdate) in (10,11,12) then 4 else 0 end as cal_quarter from dual;
cal_month - select extract(month from sysdate) from dual;
cal_week - select to_char(to_date(sysdate),'ww') from dual;
week_in_month - select to_char(to_date(sysdate),'w') from dual;
cal_st_dt_of_wk - select trunc(sysdate,'iw')-1 from dual;
cal_end_dt_of_wk - select trunc(sysdate,'iw')+5 from dual;
rfrsh_dt - select sysdate from dual;
cal_yyyymm - select to_char(sysdate,'yyyymm') from dual;
好的,内容很多 ;) 但我认为这现在应该可以了:
-- provide year as YYYY
CREATE OR REPLACE PROCEDURE fill_table (year IN VARCHAR2) IS
date_holder DATE := TO_DATE ('01.01.' || year,'DD.MM.YYYY');
BEGIN
WHILE (TO_CHAR (date_holder,'YYYY') = year) LOOP
INSERT INTO t_time
VALUES (1,
date_holder,
extract(year from date_holder),
case when extract(month from date_holder) in (1,2,3) then 1
when extract(month from date_holder) in (4,5,6) then 2
when extract(month from date_holder) in (7,8,9) then 3
when extract(month from date_holder) in (10,11,12) then 4 else 0 END,
extract(month from date_holder),
to_char(to_date(date_holder),'ww'),
to_char(to_date(date_holder),'w'),
trunc(date_holder,'iw')-1,
trunc(date_holder,'iw')+5,
sysdate ,
to_char(date_holder,'yyyymm'));
date_holder := date_holder +1;
END LOOP;
END;
/
所以基本思路是:
- 从
1.1.<YEAR>
日期开始 - 一天一天相加并按照您的描述插入值
日历周、月中周、周的开始和结束似乎有问题......无论如何 - 这种方法应该没问题。我也省略了正确的密钥计算 - 最好的选择是 SEQUENCE
.
p.s.: 检查this demo.