SQL 服务器上周从星期日到星期六

Question

我正在尝试获取从周日到上周周六的日期，我的代码是，

Declare
      @now DateTime, @fmWeek DateTime, @toWeek DateTime

Set @now = GetDate()
Set @fmWeek = Convert(DateTime, DateAdd(wk, DateDiff(wk, 0, @now), -1))
Set @toWeek = DATEADD(ms,-3,Convert(DateTime, DateAdd(wk, DateDiff(wk, 0,  @now), 6)))

select @fmWeek, @toWeek

它显示了从 2018-04-15 00:00:00.000 到 2018-04-21 23:59:59.997

的数据

我需要从前一周的太阳到坐不在同一周的日期

Answer 1

I need to get dates from previous week sun to sat not the same week

我会减去 7 天：

Declare @now DateTime = GetDate()
    ,@fmWeek DateTime, @toWeek DateTime;

Set @fmWeek = DateAdd(wk, DateDiff(wk, 0, @now), -1) - 7;
Set @toWeek = DateAdd(wk, DateDiff(wk, 0, @now), 5) - 7;
select @fmWeek, @toWeek;

DBFiddle Demo

Answer 2

如果您只想显示两个日期，@lad2025 已经为您提供了获取日期的正确查询。

如果你想显示这两天之间的所有日期，你可以尝试如下。

Declare @now DateTime = GetDate()
    ,@fmWeek DateTime, @toWeek DateTime;

Set @fmWeek = DateAdd(wk, DateDiff(wk, 0, @now), -1) - 7;
Set @toWeek = DateAdd(wk, DateDiff(wk, 0, @now), 5) - 7;

SELECT @fmWeek + RN AS DATE FROM
(   
    SELECT (ROW_NUMBER() OVER (ORDER BY (SELECT NULL)))-1 RN 
    FROM   master..[spt_values] T1
) T 
WHERE RN <= DATEDIFF(DAY,@fmWeek,@toWeek)

输出：

Date
------------------------
2018-04-08 00:00:00.000
2018-04-09 00:00:00.000
2018-04-10 00:00:00.000
2018-04-11 00:00:00.000
2018-04-12 00:00:00.000
2018-04-13 00:00:00.000
2018-04-14 00:00:00.000

SQL 服务器上周从星期日到星期六

SQL Server Last week from sun to sat

sql

tsql

sql-server

datetime

sql-server-2014