如何从两列中获取 MIN 值以及相应的 ID？

Question

我的查询 return 两列（price_base、price_special）中的最低价格，但 return 不是正确的 store_id对应于找到的最低价格。

我的查询：

SELECT grocery_item.id, grocery_item.category,
grocery_category.name AS cat, grocery_item.name AS itemName,
MIN( if( grocery_price.price_special>0,
grocery_price.price_base)) AS price,
grocery_price.store_id,
grocery_store.name AS storeName
FROM grocery_item
LEFT JOIN grocery_category ON
grocery_category.id=grocery_item.category
LEFT JOIN grocery_price
ON grocery_price.item_id = grocery_item.id
LEFT JOIN grocery_store 
ON grocery_store.id=grocery_price.store_id   
WHERE grocery_price.selection='no'
AND buy='yes'
GROUP BY grocery_price.item_id
ORDER BY store_id, grocery_item.category, grocery_item.name

Returns 这个：

ID  category    cat     itemName       price    store_id    storeName
92  3   Bread/Bakery    Arnold Bread    2.14    1           Food Lion

但是 grocery_price table 包含以下信息：

item_id price_base  price_special   store_id
92      4.29        2.14            9
92      3.99        0.00            1

所以我需要 returned 的 store_id 是 9（storeName returned 不会是 Food Lion）

编辑：基于 Uueerdo 评论的工作查询（谢谢！）

SELECT minP.item_id, gi.category, gc.name AS cat,
gi.name as itemName,  gp.store_id, 
gs.name AS storeName, minP.price
FROM
(SELECT p.item_id, MIN(IF(p.price_special >0,
p.price_special,p.price_base)) AS price
FROM grocery_item AS i
INNER JOIN grocery_price AS p ON (i.id = p.item_id)
WHERE i.buy = 'yes'
GROUP BY p.item_id) AS minP
INNER JOIN grocery_item AS gi ON minP.item_id = gi.id
INNER JOIN grocery_category AS gc on gi.category = gc.id 
LEFT JOIN grocery_price AS gp
ON minP.price = IF(gp.price_special > 0,
gp.price_special,gp.price_base)
AND gp.item_id = gi.id
INNER JOIN grocery_store AS gs ON gp.store_id = gs.id
GROUP BY gi.id
ORDER BY gs.id, gi.category,gi.name

Answer 1

为非分组、非聚合字段返回的值是从与分组字段值遇到的值中（有效地）随机选择的。大多数 RDBMS 甚至不认为这样的查询有效，甚至 MySQL 的更新版本默认也不允许这样的查询。

在像您这样的情况下，您需要与聚合结果关联的非分组值（在本例中为最小值）；聚合查询必须转换为子查询，子查询可以连接回聚合表以查找与聚合值对应的源行。

编辑：基本上，您需要稍微不同地看待问题。您目前正在查找某件商品的最低价格以及列出该商品的一家商店；您需要找到一件商品的最低价格，然后用它来找到以该价格出售该商品的商店。

这将为您提供标记为 "buy" 的商品的最低价格：

SELECT p.item_id, MIN(IF(p.price_special > 0,p.price_special,p.price_base)) AS price
FROM grocery_item AS i
INNER JOIN grocery_price AS p ON (i.id = p.item_id)
WHERE i.buy = 'yes'
GROUP BY p.item_id

然后您可以用它来得到其余的结果：

SELECT minP.item_id
   , gi.name
   , gi.category, gc.category_name AS cat, gi.Name as itemName, gi.buy
   , gp.store_id, gp.name AS storeName
   , minP.price
FROM ([the query above]) AS minP
INNER JOIN grocery_item AS gi ON minP.item_id = gi.id
INNER JOIN grocery_category AS gc on gi.category = gc.grocery_category_id 
    /* Guessing on this join since grocery_category_id 
       was not qualified with it's table name */
INNER JOIN grocery_price AS gp 
   ON minP.price = IF(gp.price_special > 0,gp.price_special,gp.price_base)
   /* Alternatively: ON minP.price IN (gp.price_special, gp.price_base) 
      ... though this could cause false positives if the minP.price is 0 
          from one store's base price being "free"
   */
INNER JOIN grocery_store AS gs ON gp.store_id = gs.id
;

如何从两列中获取 MIN 值以及相应的 ID？

How do I get the MIN value from two columns along with corresponding id?

mysql

min