在 JavaScript If..Else 语句中使用逻辑运算符“&&”时得到 "undefined" 结果

Getting "undefined" result when using the logical operator "&&" in a JavaScript If..Else statement

该代码用于根据收入 (var income) 选择联邦贫困水平 (var fpl) 百分比类别。当我 运行 这个脚本时,当我使用 && 逻辑运算符时,我的结果是 "undefined"。如果我使用 || 逻辑运算符,我会得到错误且相同的答案 - “101-185%” - 无论我使用什么数字 var income.

<p id="demo"></p>

<script>
  function FPL() {   

    var income = '4200.00';
    var fs = '1';

        var fpl;  
        if(fs == '1') {
            if(income < '1022.00')
               fpl = "0-100%";  
            if (income > '1022.00' && income < '1882.00') 
               fpl = "101-185%";   
            if (result3 > '1882.00' && income < '2033.00') 
               fpl = "186%-200%";
            if (income < '2033.00')
               fpl ="'201% & Over";

            return fpl;                

        }             

        result6 = 'Federal Poverty Level: ' + fpl;

        document.getElementById("demo").innerHTML = result6;
 }   

</script>

Else..If 语句中的逻辑运算符在 JavasScript 中的使用方式不同吗?

快速查看后,您在这一行有错误:

if (result3 > '1882.00' && income < '2033.00')

"result3" 确实未定义,请尝试使用 "income"

你的 income 值不属于你的任何 if 语句(我想,你想写 if (income > /* instead of < */ "2033.00"),所以 fpl 仍然未定义

首先,让我们检查一下你的代码,因为你有一些错误,我会在错误的地方添加评论。

注意: 比较字符串时也要小心,例如 "400" > "100000" 将 return true。所以如果你想比较值,在比较之前解析它们。

  function FPL() {   

    var income = '4200.00';
    var fs = '1';

        //set a default value here to fpl or inside an else.
        var fpl;  
        if(fs == '1') {
            //on all these ifs, you dont have an else, then if your income doesnt fill your criteria, it will be undefined.
            if(income < '1022.00')
               fpl = "0-100%";  
            if (income > '1022.00' && income < '1882.00') 
               fpl = "101-185%";   
            if (result3 > '1882.00' && income < '2033.00') //result3 doesnt even exist, this will throw an error.
               fpl = "186%-200%";
            if (income < '2033.00')
               fpl ="'201% & Over";

            // if you return here, how do you expect the following code to execute? 
            // you just needed to continue the workflow
            return fpl;                

        }             
        //this code is never executed, unless fs is different than 1 (but it is hardcoded)
        result6 = 'Federal Poverty Level: ' + fpl;

        document.getElementById("demo").innerHTML = result6;
 }   

这里你的代码没有错误并已修复。

function FPL() {
  //parse the value to get the number.
  var income = parseFloat('4200.00');
  var fs = '1';

  var fpl;
  if (fs == '1') {
    if (income < parseFloat('1022.00'))
      fpl = "0-100%";
    else if (income > parseFloat('1022.00') && income < parseFloat('1882.00'))
      fpl = "101-185%";
    else if (income > parseFloat('1882.00') && income < parseFloat('2033.00'))
      fpl = "186%-200%";
    else if (income < parseFloat('2033.00'))
      fpl = "'201% & Over";
    else
      fpl = 'default value';
  }

  result6 = 'Federal Poverty Level: ' + fpl;

  document.getElementById("demo").innerHTML = result6;
}

FPL();
<p id="demo"></p>