在 Elasticsearch 中根据匹配的最佳字段进行搜索

Question

在下面的文档中搜索 "foo bar" 会得到 name* 的累积结果，但我想获得最匹配字段的分数（即 name1 分数） .

{
  "name1": "foo bar",
  "name2": "foo",
  "name3": "bar"
}

查询例如：

{
  "query": {
    "filtered": {
      "query": {
        "bool": {
          "should": [{
            "match": {
              "name1": {
                "query": "foo bar"
              }
            }
          }, {
            "match": {
              "name2": {
                "query": "foo bar"
              }
            }
          }, {
            "match": {
              "name3": {
                "query": "foo bar"
              }
            }
          }]
        }
      }
    }
  }
}

使用 Elasticsearch 2.4

Answer 1

一个boolean query结合了所有子查询的分数。来自文档：

The bool query takes a more-matches-is-better approach, so the score from each matching must or should clause will be added together to provide the final _score for each document.

对于您的情况，您想使用另一个连接查询：The dis_max query

A query that generates the union of documents produced by its subqueries, and that scores each document with the maximum score for that document as produced by any subquery, plus a tie breaking increment for any additional matching subqueries.

示例：

{
  "query": {
    "dis_max": {
      "queries": [
        {
          "match": {
            "name1": {
              "query": "foo bar"
            }
          }
        },
        {
          "match": {
            "name2": {
              "query": "foo bar"
            }
          }
        },
        {
          "match": {
            "name3": {
              "query": "foo bar"
            }
          }
        }
      ]
    }
  }
}

*注意，我是在 ES6 上写的，它不再有 filtered 查询，但我希望你能理解要点 :)

希望对您有所帮助！

在 Elasticsearch 中根据匹配的最佳字段进行搜索

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