如何访问ADDRESS.LIST节点？

Question

我想获取ADDRESS.LISTXML节点值。我的样本 XML 是：

$result = "<ENVELOPE>
<HEADER>
    <VERSION>1</VERSION>
    <STATUS>1</STATUS>
</HEADER>
<BODY>
    <DESC></DESC>
    <DATA>
        <MESSAGE xmlns:UDF=\"TallyUDF\">
            <ADDRESS.LIST TYPE=\"String\">
                <ADDRESS>address text</ADDRESS>
                <ADDRESS>address text</ADDRESS>
                <ADDRESS>address text</ADDRESS>
                <ADDRESS>address text</ADDRESS>
            </ADDRESS.LIST>
        </MESSAGE>
    </DATA>
</BODY>
</ENVELOPE>";

我正在尝试将 PHP 用作：

$repaired = str_replace("&#4; ", "", $result);
$array_data = simplexml_load_string($repaired, 'SimpleXMLElement', LIBXML_NOERROR);

$address    = [];

$status = (string) $array_data->HEADER->STATUS;

if (strpos($status, '1') !== false) {

    $i = 0; 
    $address = array();
    foreach ($array_data->BODY->DATA->MESSAGE->'ADDRESS.LIST' as $item):

        $address[$i]['ADDRESS']     = (string) $item->ADDRESS;

        $i++;
    endforeach; 

    $response["status"] = $status;
    $response["data"]['address']  = $address;
}

echo json_encode($response);

但它显示：

Parse error: syntax error, unexpected ''ADDRESS.LIST'' (T_CONSTANT_ENCAPSED_STRING), expecting identifier (T_STRING) or variable (T_VARIABLE)" error

如何正确获取<ADDRESS.LIST>值？

Answer 1

您可以存储值变量然后使用，或者您可以通过 {}

使用它

选项 1：

$address_list = "ADDRESS.LIST";
foreach($array_data->BODY->DATA->MESSAGE->$address_list as $item):

选项 2：

foreach($array_data->BODY->DATA->MESSAGE->{'ADDRESS.LIST'} as $item):

如何访问ADDRESS.LIST节点？

How to access to ADDRESS.LIST node?

php

json

extract

xml-parsing