C++:重载 I/O 运算符
C++: overloading the I/O operators
我是 C++ 的新手,我似乎无法弄清楚重载 I/O 运算符。我已阅读:
- Overloading operator<<: cannot bind lvalue to ‘std::basic_ostream<char>&&’
- Overloading operator<<: cannot bind ‘std::basic_ostream<char>’ lvalue to ‘std::basic_ostream<char>&&’
- std::ostream {aka std::basic_ostream<char>} Ivalue to 'std::basic_ostream<char>&&
- Overloading the I/O operators on Learn cpp
但不幸的是,我做错了。我目前的代码如下:
#include <iostream>
#include <string>
// Sales_data structure
struct Sales_data {
std:: string bookNo;
unsigned units_sold = 0;
double revenue = 0.0;
};
// logic to determine if sales data are not equal
bool operator!=(const Sales_data& data1, const Sales_data& data2) {
// boolen comparision to produce not equal
return data1.bookNo != data2.bookNo;
}
ostream& operator<< (ostream &out, Sales_data &cSales_data) {
out << "(" << cSales_data.bookNo << " " << cSales_data.units_sold
<< " " << cSales_data.revenue << ")";
return out;
}
int main() {
Sales_data books; // books is of type sales_data uninitialized
double price = 0; // price is of int type initialized at 0
for (int i = 0; i >= 0; ++i) {
while (std::cin >> books.bookNo >> books.units_sold >> price) {
if (books != Sales_data()) {
i += 1;
// there is other code here but not relevant to the problem.
std::cout << books << std::endl;
}
}
}
return 0;
}
我得到的错误是
error: ‘ostream’ does not name a type
ostream& operator<< (ostream &out, Sales_data &cSales_data) {
^
exercise2_41a.cpp: In function ‘int main()’:
exercise2_41a.cpp:52:22: error: cannot bind ‘std::ostream {aka
std::basic_ostream<char>}’ lvalue to ‘std::basic_ostream<char>&&’
std::cout << books << std::endl;
我遇到问题的代码是
ostream& operator<< (ostream &out, Sales_data &cSales_data) {
out << "(" << cSales_data.bookNo << " " << cSales_data.units_sold
<< " " << cSales_data.revenue << ")";
return out;
}
但我不太确定我需要做什么才能达到预期的结果。我错过了什么?我相信我在正确的轨道上,但这也可能是一场闹剧。
std::ostream& operator<< (std::ostream &out, const Sales_data &cSales_data)
将函数中 ostream
的所有实例替换为 std::ostream
。它们是不同的,后者才是你需要的。
可选地,使 operator<<()
的第二个参数接受 const
引用。
我是 C++ 的新手,我似乎无法弄清楚重载 I/O 运算符。我已阅读:
- Overloading operator<<: cannot bind lvalue to ‘std::basic_ostream<char>&&’
- Overloading operator<<: cannot bind ‘std::basic_ostream<char>’ lvalue to ‘std::basic_ostream<char>&&’
- std::ostream {aka std::basic_ostream<char>} Ivalue to 'std::basic_ostream<char>&&
- Overloading the I/O operators on Learn cpp
但不幸的是,我做错了。我目前的代码如下:
#include <iostream>
#include <string>
// Sales_data structure
struct Sales_data {
std:: string bookNo;
unsigned units_sold = 0;
double revenue = 0.0;
};
// logic to determine if sales data are not equal
bool operator!=(const Sales_data& data1, const Sales_data& data2) {
// boolen comparision to produce not equal
return data1.bookNo != data2.bookNo;
}
ostream& operator<< (ostream &out, Sales_data &cSales_data) {
out << "(" << cSales_data.bookNo << " " << cSales_data.units_sold
<< " " << cSales_data.revenue << ")";
return out;
}
int main() {
Sales_data books; // books is of type sales_data uninitialized
double price = 0; // price is of int type initialized at 0
for (int i = 0; i >= 0; ++i) {
while (std::cin >> books.bookNo >> books.units_sold >> price) {
if (books != Sales_data()) {
i += 1;
// there is other code here but not relevant to the problem.
std::cout << books << std::endl;
}
}
}
return 0;
}
我得到的错误是
error: ‘ostream’ does not name a type ostream& operator<< (ostream &out, Sales_data &cSales_data) { ^ exercise2_41a.cpp: In function ‘int main()’: exercise2_41a.cpp:52:22: error: cannot bind ‘std::ostream {aka std::basic_ostream<char>}’ lvalue to ‘std::basic_ostream<char>&&’ std::cout << books << std::endl;
我遇到问题的代码是
ostream& operator<< (ostream &out, Sales_data &cSales_data) {
out << "(" << cSales_data.bookNo << " " << cSales_data.units_sold
<< " " << cSales_data.revenue << ")";
return out;
}
但我不太确定我需要做什么才能达到预期的结果。我错过了什么?我相信我在正确的轨道上,但这也可能是一场闹剧。
std::ostream& operator<< (std::ostream &out, const Sales_data &cSales_data)
将函数中 ostream
的所有实例替换为 std::ostream
。它们是不同的,后者才是你需要的。
可选地,使 operator<<()
的第二个参数接受 const
引用。