out-file -filepath $target -append 在 ISE 中工作，否则失败

Question

我创建了一个脚本来从 CSV 文件构建 SQL 查询文件。当我在 ISE 中运行它工作正常并完全按照我的预期构建文件。但是，如果我尝试从 powershell 或 cmd 会话启动脚本，我会收到错误消息：

Out-File : The process cannot access the file
'C:\Users\user.name\Documents\Working\terrorist525.sql' because it is
being used by another process.

脚本如下：

$start | out-file -filepath $target1 -append
$infile = $source1
$reader = [System.IO.File]::OpenText($infile)
$writer = New-Object System.IO.StreamWriter $file1;

$counter = 1
try {
    while (($line = $reader.ReadLine()) -ne $null)
    {
        $myarray=$line -split "\t" | foreach {$_.Trim()}
        if ($myarray[0] -Match "\d{1,4}\.\d{1,3}" -and $myarray[1] -ne {$null}){
$myarray[1] = $myarray[1] -replace "'","''"
$myarray[2] = $myarray[2] -replace "'","''"
$myarray[3] = $myarray[3] -replace "'","''"
$myarray[4] = $myarray[4] -replace "'","''"
$myarray[5] = $myarray[5] -replace "'","''"
"Insert into #terrorist Select convert(varchar(60),replace('OSFI Name: "+$myarray[1],$myarray[2],$myarray[3],$myarray[4],$myarray[5]+,"','''''','''')), no_,branch,name,surname,midname,usual,bname2 " | Out-File -filepath $target1 -append -force
If ($myarray[1] -eq "") {$myarray[1]=”~”}
If ($myarray[2] -eq "") {$myarray[2]=”~”}
If ($myarray[3] -eq "") {$myarray[3]=”~”}
If ($myarray[4] -eq "") {$myarray[4]=”~”}
If ($myarray[5] -eq "") {$myarray[5]=”~”}
"from cust where cust.surname in ('"+$myarray[2]+,"','"+$myarray[1]+,"','"+$myarray[3]+,"','"+$myarray[4]+,"','"+$myarray[5]+,"') and ( name in ('"+$myarray[1]+,"', '"+$myarray[2]+,"', '"+$myarray[3]+,"', '"+$myarray[4]+,"', '"+$myarray[5]+,"') or 
midname in ('"+$myarray[1]+,"', '"+$myarray[2]+,"', '"+$myarray[3]+,"', '"+$myarray[4]+,"', '"+$myarray[5]+,"') or 
usual in ('"+$myarray[1]+,"', '"+$myarray[2]+,"', '"+$myarray[3]+,"', '"+$myarray[4]+,"', '"+$myarray[5]+,"') or 
bname2 in ('"+$myarray[1]+,"', '"+$myarray[2]+,"', '"+$myarray[3]+,"', '"+$myarray[4]+,"', '"+$myarray[5]+,"') ) 
go" | Out-File -filepath $target1 -append -force

        }   

            #$writer.WriteLine($original);

            #Write-Output  $original;
            #Write-Output  $newlin
    }
}
finally {
    $reader.Close()
    $writer.Close()
}

$end1 | Out-File -filepath $target1 -append
(GC $target1).replace("?","") | Set-Content $target1

运行宁$start | add-content -path $target1时好像out-file没有放过文件我读过的所有内容都表明情况不应该如此。

Answer 1

虽然它没有回答为什么您的文件被锁定的问题，但我确实保留了一个使用 SysInternal 的 Handle.exe 从文件中删除锁定的函数。

Function Close-LockedFile{
Param(
    [Parameter(Mandatory=$true,ValueFromPipeline=$true)][Object[]]$InputFile
)
Begin{
    $HandleApp = 'C:\localbin\Handle.exe'
    If(!(Test-Path $HandleApp)){Write-Host "Handle.exe not found at $HandleApp`nPlease download it from www.sysinternals.com and save it in the afore mentioned location.";break}
}
Process{
    $HandleOut = Invoke-Expression ($HandleApp+' '+$InputFile.Fullname)
    $Locks = $HandleOut |?{$_ -match "(.+?)\s+pid: (\d+?)\s+type: File\s+(\w+?): (.+)\s*$"}|%{
        [PSCustomObject]@{
            'AppName' = $Matches[1]
            'PID' = $Matches[2]
            'FileHandle' = $Matches[3]
            'FilePath' = $Matches[4]
        }
    }
    ForEach($Lock in $Locks){
        Invoke-Expression ($HandleApp + " -p " + $Lock.PID + " -c " + $Lock.FileHandle + " -y") | Out-Null
    }
    $InputFile
}
}

Answer 2

$start | Out-File -filepath $target1 -append

$infile = $source1
$reader = [System.IO.File]::OpenText($infile)
$writer = New-Object System.IO.StreamWriter $file1;
$writer.Close()
$counter = 1
try {

通过在这个特定位置添加 $writer.close() 解决了这个问题。

out-file -filepath $target -append 在 ISE 中工作，否则失败

out-file -filepath $target -append work in ISE but fails otherwise

powershell

file

out

powershell-ise