使用分区获取工作中心的运行余额

Question

我正在编写一个脚本，它将运行在 SQL Server 2014 上。

我有一个 table 交易记录从一个工作中心转移到另一个工作中心。简化后的 table 如下：

DECLARE @transactionTable TABLE (wono varchar(10),transferDate date
                      ,fromWC varchar(10),toWC varchar(10),qty float)

INSERT INTO @transactionTable
SELECT '0000000123','5/10/2018','STAG','PP-B',10
UNION
SELECT '0000000123','5/11/2018','PP-B','PP-T',5
UNION
SELECT '0000000123','5/11/2018','PP-T','TEST',3
UNION
SELECT '0000000123','5/12/2018','PP-B','PP-T',5
UNION
SELECT '0000000123','5/12/2018','PP-T','TEST',5
UNION
SELECT '0000000123','5/13/2018','PP-T','TEST',2
UNION
SELECT '0000000123','5/13/2018','TEST','FGI',8
UNION
SELECT '0000000123','5/14/2018','TEST','FGI',2

SELECT *, 
    fromTotal = -SUM(qty) OVER(PARTITION BY fromWC ORDER BY wono, transferdate, fromWC),
    toTotal = SUM(qty) OVER(PARTITION BY toWC ORDER BY wono, transferdate, toWC)
FROM @transactionTable
ORDER BY wono, transferDate, fromWC

我想在每次交易后获得 fromWC 和 toWC 的运行ning 余额。

根据上面的记录，最终结果应该是这样的：

我相信可以使用SUM(qty) OVER(PARTITION BY...，但我不确定如何写语句。当我尝试增加和减少时，每一行总是结果为 0。

如何编写 SUM 语句来达到预期的结果？

更新

此图显示每笔交易、生成的 WC 数量，并突出显示每笔交易对应的 from 和 to 工作中心。

比如5/11看第二条记录，3条从PP-T转移到TEST。交易后PP-B有5个，PP-T有2个，TEST有3个

Answer 1

我可以接近，除了起始余额：

SELECT  wono, transferDate, fromWC, toWC, qty,
    SUM( CASE WHEN WC = fromWC THEN RunningTotal ELSE 0 END ) AS FromQTY,
    SUM( CASE WHEN WC = toWC THEN RunningTotal ELSE 0 END ) AS ToQTY
FROM( -- b
    SELECT *, SUM(Newqty) OVER(PARTITION BY WC ORDER BY wono,transferdate, fromWC, toWC) AS RunningTotal
    FROM(-- a
            SELECT wono, transferDate, fromWC, toWC, fromWC AS WC, qty, -qty AS Newqty, 'From' AS RecType
            FROM @transactionTable
            UNION ALL
            SELECT wono, transferDate, fromWC, toWC, toWC AS WC, qty, qty AS Newqty, 'To' AS RecType
            FROM @transactionTable
        ) AS a
    ) AS b
GROUP BY wono, transferDate, fromWC, toWC, qty

我的逻辑假设所有余额都从 0 开始，因此 "STAG" 余额将为 -10。

查询的工作原理：

"Unpivot" 将输入记录设置为 "From" 和 "To" 记录，并为 "From" 记录取反数量。
计算每个 "WC" 的运行总数。
将 "Unpivoted" 记录合并回原始形状

解决方案 2

WITH CTE
AS(
SELECT *,
    ROW_NUMBER() OVER( ORDER BY wono, transferDate, fromWC, toWC ) AS Sequence
FROM @transactionTable
 ),
 CTE2
 AS( 
 SELECT *,
    fromTotal = -SUM(qty) OVER(PARTITION BY fromWC ORDER BY Sequence),
    toTotal = SUM(qty) OVER(PARTITION BY toWC ORDER BY Sequence)
FROM CTE
 )
SELECT a.Sequence, b.Sequence, c.Sequence, a.wono, a.transferDate, a.fromWC, a.toWC, a.qty, a.fromTotal + ISNULL( b.toTotal, 0 ) AS FromTotal, a.toTotal + ISNULL( c.fromTotal, 0 ) AS ToTotal
FROM CTE2 AS a
    OUTER APPLY( SELECT TOP 1 * FROM CTE2 WHERE wono = a.wono AND Sequence < a.Sequence AND toWC = a.fromWC ORDER BY Sequence DESC ) AS b
    OUTER APPLY( SELECT TOP 1 * FROM CTE2 WHERE wono = a.wono AND Sequence < a.Sequence AND fromWC = a.toWC ORDER BY Sequence DESC ) AS c
ORDER BY a.Sequence

注意：此解决方案将从 "ID" 列中受益匪浅，它反映了交易顺序，或者至少您需要 wono, transferDate, fromWC, toWC[ 上的索引=13=]

使用分区获取工作中心的运行余额

Get running balance of a work center using partition

tsql

sql-server

sql-server-2014

解决方案 2

使用分区获取工作中心的 运行 余额

Get running balance of a work center using partition

tsql

sql-server

sql-server-2014

解决方案 2

使用分区获取工作中心的运行余额