正则表达式过滤字符串并将结果作为列表获取

Question

我有以下格式的字符串：

\r\nab-CD:2\r\nab-EF:1\r\nbc-DE:3\r\ndz-LF:1\r\nkr-TZ:2\r\nef-DD:1\r\nlv-ER:2\r\ndf-QW:3\r

我必须过滤掉值为 1 的 xx-XX 个值。 (xx-XX:1)

所以在示例字符串中，我必须得到的值是

ab-EF
dz-LF
ef-DD

哪个正则表达式会给我结果列表？

谢谢

Answer 1

您可以将 Regex.Matches 与以下正则表达式一起使用

[a-z]{2}-[A-Z]{2}(?=:1)

代码：

var list = Regex.Matches(input, @"[a-z]{2}-[A-Z]{2}(?=:1)")
                .Cast<Match>()
      .         .Select(match => match.Value).ToList();

Answer 2

[a-z]{2}-[A-Z]{2}(?=:1)

试试看演示。

https://regex101.com/r/fA6wE2/15

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  [a-z]{2}                 any character of: 'a' to 'z' (2 times)
--------------------------------------------------------------------------------
  -                        '-'
--------------------------------------------------------------------------------
   [A-Z]{2}                 any character of: 'A' to 'Z' (2 times)
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    :1                       ':1'
--------------------------------------------------------------------------------
  )                        end of look-ahead

正则表达式过滤字符串并将结果作为列表获取

Regex to filter string and get results as a list

c#

regex