切换音乐 On/Off 绝望

Question

这是我的 .py 文件的一部分。每次切换按钮时，我都希望 on_state 到运行，但它不起作用。我将打印语句放入测试每个部分，每次切换按钮时它都会打印 "ONSTATE!!!" 。但是 'down' 或 'normal' 状态都不会打印。

class MusicScreen(Screen):

enter = ObjectProperty(None)
text_input = ObjectProperty(None)
stop = ObjectProperty(None)
musicbutton = ToggleButton()

class MainApp(App):

def build(self):
    return presentation

def on_state(self, state, filename):
    print("ONSTATE!!!")
    sound = SoundLoader.load('/users/nolandonley/desktop/MP3/mus/' + filename + '.m4a')
    if state == "down":
        print("DOWN")
        sound.volume = .5
        sound.play()
    if state == "normal":
        print("normal")
        sound.stop()

下面是我的项目 .kv 文件。

<MusicScreen>:

text_input: text_input
id: "music"
name: "music"
BoxLayout:
    size: root.size
    pos: root.pos
    orientation: "vertical"
    FileChooserListView:
        id: filechooser
        rootpath: "/Users/nolandonley/desktop/MP3/mus"
        on_selection: text_input.text = self.selection and self.selection[0] or ''

    TextInput:
        id: text_input
        size_hint_y: None
        height: 50
        multiline: False
    ToggleButton:
        #pos: 44, 30
        size_hint: 1, .2
        text: "Play/Stop By File"
    ToggleButton:
        id: musicbutton
        #pos: 44, 30
        size_hint: 1, .2
        text: "Play/Stop By Title"
        on_state: app.on_state(self, text_input.text)

Answer 1

停止播放音乐

使用 ObjectProperty 和 sound.unload() 方法停止播放音乐。

main.py

class MainApp(App):
    sound = ObjectProperty(None, allownone=True)

    def build(self):
        return ScreenManagement()

    def on_state(self, state, filename):
        print("ONSTATE!!!")
        print("\tstate=", state)

        if self.sound is None:
            self.sound = SoundLoader.load(filename)

        # stop the sound if it's currently playing
        if self.sound.status != 'stop':
            self.sound.stop()

        if state == "down":
            self.sound.volume = .5
            self.sound.play()
        else:   # if state == "normal":
            if self.sound:
                self.sound.stop()
                self.sound.unload()
                self.sound = None

传递切换按钮的状态

它不起作用，因为您正在传递一个对象，即切换按钮的一个实例。

替换

on_state: app.on_state(self, text_input.text)

与

on_state: app.on_state(self.state, text_input.text)

备注

一个[Toggle Button][1]只有两个状态，即正常和向下。因此，您不需要两个 if 语句。通过以下方式提高 Kivy 应用程序的性能：

正在替换

if state == "down":
    print("DOWN")
    sound.volume = .5
    sound.play()
if state == "normal":
    print("normal")
    sound.stop()

与：

print(state)
if state == "down":
    sound.volume = .5
    sound.play()
else:   # if state == "normal":
    sound.stop()

切换音乐 On/Off 绝望

Toggle music On/Off Kivy

togglebutton

python-3.x

kivy

停止播放音乐

main.py

传递切换按钮的状态

备注