无法理解 interface/struct 关系
Having trouble understanding interface/struct relationship
我很难理解接口和结构之间的关系。我声明了一个名为 Datatype
的接口,如下所示:
package main
type Datatype interface {
Unmarshal(record []string) error
String() string
}
我还创建了几个实现此接口的结构。这是一个简单的例子:
package main
import (
"encoding/csv"
"fmt"
"gopkg.in/validator.v2"
"reflect"
"strconv"
"time"
)
type User struct {
Username string `validate:"nonzero"`
UserId string `validate:"nonzero"`
GivenName string `validate:"nonzero"`
FamilyName string `validate:"nonzero"`
Email string `validate:"regexp=^[0-9a-zA-Z]+@[0-9a-zA-Z]+(\.[0-9a-zA-Z]+)+$"`
SMS string `validate:"nonzero"`
Phone string `validate:"min=10"`
DateOfBirth time.Time
}
type Users []User
func (u *User) Unmarshal(record []string) error {
s := reflect.ValueOf(u).Elem()
if s.NumField() != len(record) {
return &FieldMismatch{s.NumField(), len(record)}
}
for i := 0; i > s.NumField(); i++ {
f := s.Field(i)
switch f.Type().String() {
case "string":
f.SetString(record[i])
case "int", "int64":
ival, err := strconv.ParseInt(record[i], 10, 0)
if err != nil {
return err
}
f.SetInt(ival)
default:
return &UnsupportedType{f.Type().String()}
}
}
return nil
}
func (u *User) String() string {
return fmt.Sprintf("%#v", u)
}
func (u *User) populateFrom(reader *csv.Reader) (Users, error) {
var users Users
for {
record, err := reader.Read()
check(err)
err = u.Unmarshal(record)
check(err)
valid := validator.Validate(u)
if valid == nil {
user := *u
users = append(users, user)
} else {
fmt.Println("Validation error?: ", valid)
}
}
return users, nil
}
问题:
如您所见,我还有一个名为 Users
的类型,它就是 []User
。当我尝试从 return 类型为 []Datatype
的函数中 return 这种类型时,我收到以下错误消息:
cannot use results (type Users) as type []Datatype in return argument
我确定我遗漏了一些明显的东西,但在我看来这应该可行。
问题:
有人可以解释为什么它不起作用吗?有没有更好(更惯用)的方法来实现这个最终结果?
切片不是协变的;尽管 User
实现了 Datatype
,但 []User
没有实现 []Datatype
(因为 nothing 实现了 []Datatype
:它本身就是不是接口类型,它只是一个元素类型是接口类型的切片类型。
编辑添加: As Dave C points out in a comment above, a closely-related question appears in the Go FAQ. [link] Go 常见问题解答以与 Stack Exchange 内容兼容的方式获得许可,因此,这是完整的问题:
Can I convert a []T to an []interface{}?
Not directly, because they do not have the same representation in memory. It is necessary to copy the elements individually to the destination slice. This example converts a slice of int
to a slice of interface{}
:
t := []int{1, 2, 3, 4}
s := make([]interface{}, len(t))
for i, v := range t {
s[i] = v
}
我很难理解接口和结构之间的关系。我声明了一个名为 Datatype
的接口,如下所示:
package main
type Datatype interface {
Unmarshal(record []string) error
String() string
}
我还创建了几个实现此接口的结构。这是一个简单的例子:
package main
import (
"encoding/csv"
"fmt"
"gopkg.in/validator.v2"
"reflect"
"strconv"
"time"
)
type User struct {
Username string `validate:"nonzero"`
UserId string `validate:"nonzero"`
GivenName string `validate:"nonzero"`
FamilyName string `validate:"nonzero"`
Email string `validate:"regexp=^[0-9a-zA-Z]+@[0-9a-zA-Z]+(\.[0-9a-zA-Z]+)+$"`
SMS string `validate:"nonzero"`
Phone string `validate:"min=10"`
DateOfBirth time.Time
}
type Users []User
func (u *User) Unmarshal(record []string) error {
s := reflect.ValueOf(u).Elem()
if s.NumField() != len(record) {
return &FieldMismatch{s.NumField(), len(record)}
}
for i := 0; i > s.NumField(); i++ {
f := s.Field(i)
switch f.Type().String() {
case "string":
f.SetString(record[i])
case "int", "int64":
ival, err := strconv.ParseInt(record[i], 10, 0)
if err != nil {
return err
}
f.SetInt(ival)
default:
return &UnsupportedType{f.Type().String()}
}
}
return nil
}
func (u *User) String() string {
return fmt.Sprintf("%#v", u)
}
func (u *User) populateFrom(reader *csv.Reader) (Users, error) {
var users Users
for {
record, err := reader.Read()
check(err)
err = u.Unmarshal(record)
check(err)
valid := validator.Validate(u)
if valid == nil {
user := *u
users = append(users, user)
} else {
fmt.Println("Validation error?: ", valid)
}
}
return users, nil
}
问题:
如您所见,我还有一个名为 Users
的类型,它就是 []User
。当我尝试从 return 类型为 []Datatype
的函数中 return 这种类型时,我收到以下错误消息:
cannot use results (type Users) as type []Datatype in return argument
我确定我遗漏了一些明显的东西,但在我看来这应该可行。
问题:
有人可以解释为什么它不起作用吗?有没有更好(更惯用)的方法来实现这个最终结果?
切片不是协变的;尽管 User
实现了 Datatype
,但 []User
没有实现 []Datatype
(因为 nothing 实现了 []Datatype
:它本身就是不是接口类型,它只是一个元素类型是接口类型的切片类型。
编辑添加: As Dave C points out in a comment above, a closely-related question appears in the Go FAQ. [link] Go 常见问题解答以与 Stack Exchange 内容兼容的方式获得许可,因此,这是完整的问题:
Can I convert a []T to an []interface{}?
Not directly, because they do not have the same representation in memory. It is necessary to copy the elements individually to the destination slice. This example converts a slice of
int
to a slice ofinterface{}
:t := []int{1, 2, 3, 4} s := make([]interface{}, len(t)) for i, v := range t { s[i] = v }