大查询按分组字段排序

Question

我有一个按日期分组的查询，效果很好。

SELECT EXTRACT(date FROM DATETIME(timestamp, 'US/Eastern')) date, SUM(users) total_users FROM `mydataset.mytable` 
GROUP BY EXTRACT(date FROM DATETIME(timestamp, 'US/Eastern'))

但是当我尝试按日期排序时：

SELECT EXTRACT(date FROM DATETIME(timestamp, 'US/Eastern')) date, SUM(users) total_users FROM `mydataset.mytable` 
GROUP BY EXTRACT(date FROM DATETIME(timestamp, 'US/Eastern'))
ORDER BY EXTRACT(date FROM DATETIME(timestamp, 'US/Eastern'));

我收到以下错误：

SELECT list expression references column timestamp which is neither grouped nor aggregated at [1:35]

时间戳列显然是分组依据的一部分，甚至更奇怪的是它在没有 ORDER BY 子句的情况下也能工作...这是怎么回事？

Answer 1

您可以尝试子选择：

#standardSQL
SELECT
  date,
  total_users
FROM (
  SELECT
    EXTRACT(date FROM DATETIME(timestamp,'US/Eastern')) date,
    SUM(users) total_users
  FROM
   `mydataset.mytable`
  GROUP BY EXTRACT(date FROM DATETIME(timestamp, 'US/Eastern'))
  )
ORDER BY
   date

Answer 2

#standardSQL
SELECT 
  EXTRACT(DATE FROM DATETIME(timestamp, 'US/Eastern')) date, 
  SUM(users) total_users 
FROM `mydataset.mytable` 
GROUP BY 1
ORDER BY 1