TS2339：联合类型上不存在属性 - 属性字符串 |不明确的

Question

我的联合类型有问题，如下所示：

type RepeatForm = {
    step:
        | {
              repeat: false;
          }
        | {
              repeat: true;
              from: undefined;
          }
        | {
              repeat: true;
              from: string;
              by?: string;
          };
};

我有以下函数，我想在其中获取 by 的值（如果它存在）：

export const getByField = (form: RepeatForm) => {
    if (form.step.repeat === false || form.step.from === undefined) {
        return null;
    }
    const x = form.step.from;
    return form.step.by;
};

我收到此错误：Property 'by' does not exist on type '{ repeat: true; from: undefined; } | { repeat: true; from: string; by?: string | undefined; }'. Property 'by' does not exist on type '{ repeat: true; from: undefined; }'.

这让我非常困惑，因为 TypeScript 知道 form.step.from 与 undefined 不同，他甚至将变量类型 x 插入到 string。

这个问题的原因是什么？那我怎样才能访问by属性呢？

Answer 1

用于区分联合的原始 PR 非常具体地说明区分字段必须是 string 文字类型（可以选择添加对 boolean 和 number 似乎已经发生的文字类型）。因此，您根据字段类型（string 与 undefined）进行区分的用例似乎不受支持。这不起作用，例如：

let u!: { v: number, n: number } | { v: string, s: string}
if(typeof u.v === 'number') {
    u.n // not accesible, type not narrowed 
}

我们可以使用条件类型和自定义类型保护来实现：

function isUndefined<T, K extends keyof T>(value : T, field: K) : value is Extract<T, { [P in K] : undefined }> {
    return !!value[field]
}

export const getByField = (form: RepeatForm) => {
    if (form.step.repeat === false || isUndefined(form.step, 'from')) {
        return null;
    }
    const x = form.step.from;
    return form.step.by;
};

我们还可以创建此函数的通用版本，允许按任何类型缩小：

type ExtractKeysOfType<T, TValue> = { [P in keyof T]: T[P] extends TValue ? P : never}[keyof T]

function fieldOfType<T, K extends ExtractKeysOfType<T, string>>(value : T, field: K, type: 'string'): value is Extract<T, { [P in K] : string }>
function fieldOfType<T, K extends ExtractKeysOfType<T, number>>(value : T, field: K, type: 'number'): value is Extract<T, { [P in K] : number }>
function fieldOfType<T, K extends ExtractKeysOfType<T, boolean>>(value : T, field: K, type: 'boolean'): value is Extract<T, { [P in K] : boolean }>
function fieldOfType<T, K extends ExtractKeysOfType<T, Function>>(value : T, field: K, type: 'function'): value is Extract<T, { [P in K] : Function }>
function fieldOfType<T, K extends ExtractKeysOfType<T, symbol>>(value : T, field: K, type: 'symbol'): value is Extract<T, { [P in K] : symbol }>
function fieldOfType<T, K extends ExtractKeysOfType<T, object>>(value : T, field: K, type: 'object'): value is Extract<T, { [P in K] : object }>
function fieldOfType<T, K extends ExtractKeysOfType<T, undefined>>(value : T, field: K, type: 'undefined'): value is Extract<T, { [P in K] : undefined }>
function fieldOfType<T, K extends keyof T, TValue extends T[K]>(value : T, field: K, type: new (...args:any[])=> TValue): value is Extract<T, { [P in K] : TValue }>
function fieldOfType<T, K extends keyof T>(value : T, field: K, type: string| Function) :boolean {
    if(typeof type === 'string') {
        return typeof value[field] === type;
    } else {
        return value[field] instanceof type
    }
}

const getByField = (form: RepeatForm) => {
    if (form.step.repeat === false || fieldOfType(form.step, 'from', 'undefined')) {
        return null;
    }
    const x = form.step.from;
    return form.step.by;
};


let u: { v: number, n: number } | { v: string, s: string}={ v: 0, n : 10};
if(fieldOfType(u, 'v', 'number')) {
    console.log(u.n);
}

class A {private a: undefined;}
class B {private b: undefined;}
let uc: { v: A, n: number } | { v: B, s: string} = Math.random() > 0.5 ? { v: new B(), s: '10' } : { v: new A(), n: 10 };
if(fieldOfType(uc, 'v', A)) {
    console.log(uc.n)
}

TS2339：联合类型上不存在属性 - 属性字符串 |不明确的

TS2339: Property does not exist on union type - property string | undefined

types

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TS2339：联合类型上不存在 属性 - 属性 字符串 |不明确的

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types

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TS2339：联合类型上不存在属性 - 属性字符串 |不明确的